For number 3 what are the experimental Cp, Literature Cp 1 and 2 and the percent yi

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For number 3 what are the experimental Cp, Literature Cp 1 and 2 and the percent yi

1st Type of Metal: wm
Mass of Cups & Water
152.5g
179.29
10.19
Mass of Cups & Water
Mass of Cups
Mass of Cups
Mass of Water (in calorimeter) 24
27°C
Mass of Water (in calorimeter) 69,19
27°C
S४°८
Initial Temp. of Water
Use for #1
below
Initial Temp. of Water
*Final Temp of Water
*Final Temp of Water
27:89
32°C
Mass of metal
Mass of metal
33¢ Use for #2
88°C
Initial Temp. Hot Metal
below
Initial Temp. Hot Metal
* Final Temp. Metal
(in calorimeter)
*Final Temp. Metal
(in calorimeter)
*= same temp.
Results:
1. Calculate the heat gained by the water (lost by the substance) in the calorimeter using the equation
in the Introduction. Remember to write the units!!
Q for water using 1st Metal
Quater = mwater X (Tf- Tiwater X Cp water
Q for water using 2nd Metal
Qwater = mwater x (Tf-Ti)water x Cp wat
water
2. Calculate the specific heat of the substance using the answer from number 1 and the equation in
the Introduction. Now, Cp is your unknown since you're using Q from #1.
Cp of 1st Metal
Cp for 2nd Metal
x Cp
Qsubst = msubst X (Ti- Tf)subst
Qsubst
subst
Qsubst = msubst X (Tj- Tf)subat X Cp
Qsubst
%3D
%3D
maubst X (Ti- Tf) subat
msubat X (Ti-T) subst
21923.67
184522
Cp = 30.33
3 sf
Cp =
76.09
J/g- C
J/g - C
%3D
3 sf
3. Look up the specific heat of your substance samples and find your percent error.
Substance # 2: Experimental Cp
Substance #1: Experimental Cp
Substance #2: Literature Cp
Substance #1: Literature Cp
Percent Yield:
Percent Yield:
Transcribed Image Text:1st Type of Metal: wm Mass of Cups & Water 152.5g 179.29 10.19 Mass of Cups & Water Mass of Cups Mass of Cups Mass of Water (in calorimeter) 24 27°C Mass of Water (in calorimeter) 69,19 27°C S४°८ Initial Temp. of Water Use for #1 below Initial Temp. of Water *Final Temp of Water *Final Temp of Water 27:89 32°C Mass of metal Mass of metal 33¢ Use for #2 88°C Initial Temp. Hot Metal below Initial Temp. Hot Metal * Final Temp. Metal (in calorimeter) *Final Temp. Metal (in calorimeter) *= same temp. Results: 1. Calculate the heat gained by the water (lost by the substance) in the calorimeter using the equation in the Introduction. Remember to write the units!! Q for water using 1st Metal Quater = mwater X (Tf- Tiwater X Cp water Q for water using 2nd Metal Qwater = mwater x (Tf-Ti)water x Cp wat water 2. Calculate the specific heat of the substance using the answer from number 1 and the equation in the Introduction. Now, Cp is your unknown since you're using Q from #1. Cp of 1st Metal Cp for 2nd Metal x Cp Qsubst = msubst X (Ti- Tf)subst Qsubst subst Qsubst = msubst X (Tj- Tf)subat X Cp Qsubst %3D %3D maubst X (Ti- Tf) subat msubat X (Ti-T) subst 21923.67 184522 Cp = 30.33 3 sf Cp = 76.09 J/g- C J/g - C %3D 3 sf 3. Look up the specific heat of your substance samples and find your percent error. Substance # 2: Experimental Cp Substance #1: Experimental Cp Substance #2: Literature Cp Substance #1: Literature Cp Percent Yield: Percent Yield:
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