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5 m B 21 A -4 m- I с I D 200 KN 3 m E = constant = 70 GPa I = 1,290 (106) mm4

5 m B 21 A -4 m- I с I D 200 KN 3 m E = constant = 70 GPa I = 1,290 (106) mm4

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Using Moment area method, calculate the horizontal deflection of Joint D in the structure shown in Figure for Question 2 (a) below. I = 1290×106 mm².
Transcribed Image Text:Using Moment area method, calculate the horizontal deflection of Joint D in the structure shown in Figure for Question 2 (a) below. I = 1290×106 mm².
5m B 21 -4 m I с I D 200 KN 3 m E = constant = 70 GPa I = 1,290 (106) mm4
Transcribed Image Text:5m B 21 -4 m I с I D 200 KN 3 m E = constant = 70 GPa I = 1,290 (106) mm4
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I cannot understand these

For point of contraflexural,

40090300=200×x90300

x=2 m

θA=0 (fixed support)

θDA=θD-θA=θD=Area of MEI Dia between A and D

     = 19030012×600×3+600×4+12×300×3-12×200×2

     =355090300

θD=0.03931 radianθD= 2.252°

Deflection at point D

∆D=31-CosθD

∆D=2.3176×10-3 mm

Deflection at point D is 2.3176×10-3 mm

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why 40090300=200×x90300

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