For sorting a portion of array from index 3 to 16, Merge Sort is called What will be the last function call before the actual Merging' a. MergeSort(Array,9,16) b. None of these C. MergeSort(Array.3.4) d. MergeSort(Array,3.9) Don't Explain
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For sorting a portion of array from index 3 to 16, Merge Sort is called What will be the last function call before the actual Merging'
a. MergeSort(Array,9,16)
b. None of these
C. MergeSort(Array.3.4)
d. MergeSort(Array,3.9)
Don't Explain
Step by step
Solved in 2 steps
- The program is the same as shown at the end of the Merge sort section, with the following changes: Numbers are entered by a user in a separate helper function, ReadNums(), instead of defining a specific array in main(). The first number is how many integers to be sorted, and the rest are the integers. Output of the array has been moved to the helper function PrintNums(). An output has been added to MergeSort(), showing the indices that will be passed to the recursive function calls. Add code to the merge sort algorithm to count the number of comparisons performed. Add code at the end of main() that outputs "comparisons: " followed by the number of comparisons performed (Ex: "comparisons: 12") Hint: Use a global variable to count the comparisons. Note: Take special care to look at the output of each test to better understand the merge sort algorithm.C++ Write one program with a menu allowing a user to select either an Insertion, a Selection, a Merge or a bubble sort to run with each sort using the following data in this order for every sort. (Numbers to sort: 6, 1,13,7,11,9,2,8,15,5,3,4,12,10,14) Keep count of the total number of movement of data for each sort and at the end of running all of the sorts, print a chart showing the number of moves for each sort.Develop a merge implementation that reduces the extra space requirement to max(M, N/M), based on the following idea: Divide the array into N/M blocks of size M (for simplicity in this description, assume that N is a multiple of M). Then, (i) considering the blocks as items with their first key as the sort key, sort them using selection sort; and (ii) run through the array merging the first block with the second, then the second block with the third, and so forth.
- Java Merge Sort but make it read the data 12, 11, 13, 5, 6, 7 from a file not an array /* Java program for Merge Sort */ class MergeSort { // Merges two subarrays of arr[]. // First subarray is arr[l..m] // Second subarray is arr[m+1..r] void merge(int arr[], int l, int m, int r) { // Find sizes of two subarrays to be merged int n1 = m - l + 1; int n2 = r - m; /* Create temp arrays */ int L[] = new int[n1]; int R[] = new int[n2]; /*Copy data to temp arrays*/ for (int i = 0; i < n1; ++i) L[i] = arr[l + i]; for (int j = 0; j < n2; ++j) R[j] = arr[m + 1 + j]; /* Merge the temp arrays */ // Initial indexes of first and second subarrays int i = 0, j = 0; // Initial index of merged subarray array int k = l; while (i < n1 && j < n2) { if (L[i] <= R[j]) { arr[k] = L[i];…Following is the partition function for quicksort, where we have used the leftmost number as a pivot. Assume that our array, ARR = {14, 8, 7, 38, 22, 15, 9}, which is 7 in size. What will be the array ARR after we apply "partition(A, 0, 6)"* 9, 15, 22, 38, 7, 8, 14 7, 8, 9, 14, 15, 22, 38 9, 8, 14, 7, 22, 15, 38 9, 8, 7, 14, 22, 15, 38 7, 9, 15, 22, 38, 14, 6 38, 22, 15, 14, 9, 8, 7Develop a merging implementation based on the following idea to reduce the required extra space to max(M, N/M): For the purpose of simplicity, split the array into N/M blocks of size M and assume that N is a multiple of M. Following that, (i) use selection sort to order the blocks, treating them as items and using their first key as the sort key; and (ii) iterate over the array, merging the first block with the second, the second block with the third, and so on. Develop a merging implementation based on the following idea to reduce the required extra space to max(M, N/M): For the purpose of simplicity, split the array into N/M blocks of size M and assume that N is a multiple of M. Following that, (i) use selection sort to order the blocks, treating them as items and using their first key as the sort key; and (ii) iterate over the array, merging the first block with the second, the second block with the third, and so on. Develop a merging implementation based on the following idea to…
- Write a program to compute the exact value of the number of array accesses usedby top-down mergesort and by bottom-up mergesort. Use your program to plot the values for N from 1 to 512, and to compare the exact values with the upper bound 6N lg NGiven the following array, what is the content of the array after Two levels of merge function calls applied in Merge Sort with function call MergeSort(array, 0, 5); array: 44 12 50 3 40 23 Question 3 options: 44 12 50 3 23 40 12 44 50 3 23 40 12 3 40 23 44 50 3 12 23 40 44 50Mergesort is a complicated process, but what is it actually doing? We are going to take a closer look at the process in this exercise. You are given the merge sort algorithm and you need to add some print statements so that you can see what actually is happening. Add a print statement at each step, as well as print out the array each time. Your output needs to match the sample below. Here is a portion of a sort as an example: Unsorted: 5 3 4 1 6 9 2 7 Splitting ... *** Left: 5 3 4 1 *** Right: 6 9 2 7 Splitting ... *** Left: 5 3 *** Right: 4 1 Splitting ... *** Left: 5 *** Right: 3 Merging ... *** Current: 3 5 ... Merging ... *** Current: 2 6 7 9 Merging ... *** Current: 1 2 3 4 5 6 7 9 Sorted: 1 2 3 4 5 6 7 9
- Using merge sort, describe in pseudocode and with a flow chart how to sort an array with different fruit names like Banana, Pineapple, Pear, Kiwi, Apple, Orange, Peach, Mangoe.Below is the exercise for unsorted arrays. True or False: For each statement below, indicate whether you think it is True or False 3) For the insert function, if the array is empty, there are no comparison operations that need to be performed and you can immediately add the new element 5) Because the update algorithm depends on using linear search, its performance is O(1) in the worst case scenario 6) If you search for and delete an element in an unsorted array and then shift the rest of the elements to fill the hole, the worst case performance is O(n) 7) If you search for and delete an element in an unsorted array and then move the last element to fill the hole, the worst case performance is O(n)An array with any number of elements is said to be repeating if any two or more of the elements are appearing in sequential an indexes after each other.Write a C++ function that accepts an integer array and returns 1 or “Repeating” if it is a repeating array, otherwise it returns 0 or “Not Repeating”. For Instance:2, 3, 5, 6, 7, 7, 7, 6, 8, 10 - Repeating2, 3, 4, 6, 4, 6, 4, 7, 8, 9 - Not repeating