For the amplifier shown in Figure 1, the BJT parameters are ß = 75, Vaz (on) = 0.7 V, VCE (sat) = 0.3 V, VA = 100, and V, 25 mv. Voc=9V R = 27 ka 22 ka Rs = 10 ka Ca! E R= C2 kQ R2 = 15 k2 12 kQ The value of the DC base current Ig is
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![For the amplifier shown in Figure 1, the BJT parameters are ß = 75, Vag (on) =
0.7 V, VCE (sat) = 0.3 V, VA = 100, and V, 25 mv.
Voe=9V
R=
27 ka
22 ka
Rs =
10 ka Ca
ER=
2 k2
R=
15 k2
12 kQ
The value of the DC base current Ig is](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1f3a584f-f669-4bf6-9d10-bb210264abd3%2Fb21b4042-b602-4645-8905-774e64b985df%2Fi4zlwrs_processed.jpeg&w=3840&q=75)
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