For the circuit in the figure below, if R = 1.7 ko, RL = 1.6 kn, AVINL 1) = 13, Av(NL_2) = -64, Av(NL_3) = -95 and Av(NL 4) = 51, then the voltage gain (Av;3) is: Stage 4 Zn=10 Q Z 1 k Stage 1 Z=10 k2 Z=20 Q Z,=10 0 R. Z=7 kO Stage 2 Vo3 Z=50 N Z= 1 kQ Stage 3 -3519 o 443.3 O-232.2 o-559.4 -675 6

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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For the circuit in the figure below, if R = 1.7 ko, RL = 1.6 kN, Av(NL 1) =
13, Av(NL_ 2) = -64, Av(NL_3) = -95 and Av(NL 4) = 51 then the voltage gain (Av,3) is:
%3D
%3D
Stage 4
Z =10 0
Z=1 ko
R.
Stage 1
Vo2
Z=10 kQ
Z=20 Q
R
Z,=10 Q
Z7 k2
Stage 2
Z=50 N
Z= 1 kQ
Stage 3
0-3519
o 443.3
o -232.2
o-559.4
o-675.6
Transcribed Image Text:For the circuit in the figure below, if R = 1.7 ko, RL = 1.6 kN, Av(NL 1) = 13, Av(NL_ 2) = -64, Av(NL_3) = -95 and Av(NL 4) = 51 then the voltage gain (Av,3) is: %3D %3D Stage 4 Z =10 0 Z=1 ko R. Stage 1 Vo2 Z=10 kQ Z=20 Q R Z,=10 Q Z7 k2 Stage 2 Z=50 N Z= 1 kQ Stage 3 0-3519 o 443.3 o -232.2 o-559.4 o-675.6
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