For the function y =f(x) – 2x' + 0:dfa. Findat4.dxf'(-4) =96b. Find a formula for zf '(y).1.dfdyC. Findat y/(--4).(7)'UC - 4)).

Answer: a.) ddf(2x3+0) = 6x2 =f'(x)f'(-4) = 6×(-4)2 = 96 b.) y = f(x) = y = f(x) = 2x3 + 0y = 2x3…

Answered: For the function y - f(x)- 2x + 0: df…

For the function y - f(x)- 2x + 0: df at = d.x a. Find 4. f'(-4) = 96 b. Find a formula for a 1 df at y f(-4). dy C. Find (f )(-4)

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

Chapter2: Graphical And Tabular Analysis

Section2.1: Tables And Trends

Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...

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Question

For the function y =
f(x) – 2x' + 0:
df
a. Find
at
4.
dx
f'(-4) =
96
b. Find a formula for z
f '(y).
1.
df
dy
C. Find
at y
/(--4).
(7)'UC - 4)).

Expert Solution

Step 1

Answer:

a.)

$\frac{d}{d f} (2 x^{3} + 0) = 6 x^{2} = f' (x) f' (- 4) = 6 \times {(- 4)}^{2} = 96$

b.)

y = f(x) = $y = f (x) = 2 x^{3} + 0 y = 2 x^{3} + 0 x = \frac{1}{2} (\sqrt[3]{y}) N o w y = f (x) t h e r e f o r e x = f^{- 1} (y) S o f^{- 1} (y) = \frac{1}{2} (\sqrt[3]{y})$

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