For the given signal, x(t) = 3+ 1 sin(0.5x t)–0.3 sin(4.5x t+120°)–2.2 cos(0.5n t) +6 e/0.257 í +6 e 70.25x t Find the Fouries series coefficient, a2

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とs2
1 (.2k 6)
ksl8
大=2
- 2-2 Cos (o.eskt)
1,
+ 12 ( Cos ( •.2571t))
* 1 1+2-27
= 3-2
(3)
い
Transcribed Image Text:とs2 1 (.2k 6) ksl8 大=2 - 2-2 Cos (o.eskt) 1, + 12 ( Cos ( •.2571t)) * 1 1+2-27 = 3-2 (3) い
For the given signal,
x(t) = 3+ 1 sin(0.5x t)–0.3 sin(4.5x t+120°)–2.2 cos(0.5n t) +6 e/0.25x t +6 e j0.25, t
Find the Fouries series coefficient, a2
Transcribed Image Text:For the given signal, x(t) = 3+ 1 sin(0.5x t)–0.3 sin(4.5x t+120°)–2.2 cos(0.5n t) +6 e/0.25x t +6 e j0.25, t Find the Fouries series coefficient, a2
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