For the given vector function below, find the equation of the plane that contains the osculating circle . = (t,2t²,t³), t= 1 6x - 2y +z = 6 а. b. 6x - 3y +2z = 2 с. 6x + 4z = 10 d. 12x - 2y +z = 9 6х - 2y +2z%3D4 е.

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Chapter5: Inner Product Spaces
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For the given vector function below, find the equation of the plane that contains the osculating
circle .
= (t,2t²,t³), t= 1
6x - 2y +z = 6
а.
b. 6х-Зу+22%3D2
6x + 4z = 10
12x - 2y +z = 9
6x – 2y + 2z = 4
с.
d.
е.
Transcribed Image Text:For the given vector function below, find the equation of the plane that contains the osculating circle . = (t,2t²,t³), t= 1 6x - 2y +z = 6 а. b. 6х-Зу+22%3D2 6x + 4z = 10 12x - 2y +z = 9 6x – 2y + 2z = 4 с. d. е.
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