i need the answer quickly . For the reinforced concrete floor shown in the Figure below, design the slab to carryservice live load 6 and dead load due to:KNINSelf-weight, 5 cm tiles, 2 cm mortar, 2 cm plaster and 3- partition.f = 25 MPa, fy 420 MPa. For concrete use density=24, for tiles, mortar and plasterused density=204.9 m-7m

Solution: Given: LL = 6 kN/m2 fc = 25 MPa fy = 420 MPa concrete density = 24 kN/m3 Plaster density =…

For the reinforced concrete floor shown in the Figure below, design the slab to carry service live load 6 and dead load due to: KN Self-weight, 5 cm tiles, 2 cm mortar, 2 cm plaster and 3 partition. AN f = 25 MPa, fy 420 MPa. For concrete use density-24 for tiles, mortar and plaster used density-20 KN 4.9 m- 7m

For the reinforced concrete floor shown in the Figure below, design the slab to carry service live load 6 and dead load due to: KN Self-weight, 5 cm tiles, 2 cm mortar, 2 cm plaster and 3 partition. AN f = 25 MPa, fy 420 MPa. For concrete use density-24 for tiles, mortar and plaster used density-20 KN 4.9 m- 7m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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