for the roots of each equation. 55. 2r-5x² + 6 = 0 56. 2r3 - x2 - 5x + 3 = 57. 4x + 8x2 - 11x 15 = 0

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Polynomial And Rational Functions
Section9.2: Remainder And Factor Theorems
Problem 53PS
icon
Related questions
Question
! please solve question number 59
Use the theorem on bounds to establish the best integral bounds
for the roots of each equation.
55. 2r-5x² + 6 = 0
56. 2x-x2- 5x + 3 = 0
57. 4x + 8x2
11x 15 0
|
58. 6x + 5x2 - 36x - 35 = 0
59, w - 5w3 + 3w2 + 2w - 1 = 0
|
60. 3z4 - 7z2 + 5 = 0
61. -2x + 5x2 – 3x + 9 = 0
62. -x + 8x – 12 = 0
Use the rational zero theorem, Descartes's rule of signs, and the
theorem on bounds as aids in finding all real and imaginary roots
to each equation.
63 x - 4x2 – 7x + 10 = 0
Transcribed Image Text:Use the theorem on bounds to establish the best integral bounds for the roots of each equation. 55. 2r-5x² + 6 = 0 56. 2x-x2- 5x + 3 = 0 57. 4x + 8x2 11x 15 0 | 58. 6x + 5x2 - 36x - 35 = 0 59, w - 5w3 + 3w2 + 2w - 1 = 0 | 60. 3z4 - 7z2 + 5 = 0 61. -2x + 5x2 – 3x + 9 = 0 62. -x + 8x – 12 = 0 Use the rational zero theorem, Descartes's rule of signs, and the theorem on bounds as aids in finding all real and imaginary roots to each equation. 63 x - 4x2 – 7x + 10 = 0
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer