For the simply supported beam subjected to the loading shown, derive equations for the shear force Vand the bending moment M for any location in the beam. (Place the origin at point A.) Let w = 19.0 kips/ft, a=5.0 ft, and b-15.5 ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. B

International Edition---engineering Mechanics: Statics, 4th Edition
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Chapter6: Beams And Cables
Section: Chapter Questions
Problem 6.42P: For the beam AB shown in Cases 1 and 2, derive and plot expressions for the shear force and bending...
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For the simply supported beam subjected to the loading shown, derive equations for the shear force Vand the bending moment M
for any location in the beam. (Place the origin at point A.) Let w = 19.0 kips/ft, a=5.0 ft, and b=15.5 ft. Construct the shear-force
and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this G0 exercise.
Calculate the reaction forces By and Cyacting on the beam. Positive values for the reactions are indicated by the directions of the
red arrows shown on the free-body diagram below. (Note: Since Bx = 0, it has been omitted from the free-body diagram.)
B
C
b
By
Cy
Answers:
By =
i
kips
Cy =
i
kips
Transcribed Image Text:For the simply supported beam subjected to the loading shown, derive equations for the shear force Vand the bending moment M for any location in the beam. (Place the origin at point A.) Let w = 19.0 kips/ft, a=5.0 ft, and b=15.5 ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this G0 exercise. Calculate the reaction forces By and Cyacting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Bx = 0, it has been omitted from the free-body diagram.) B C b By Cy Answers: By = i kips Cy = i kips
(a) x = 5.0- ft (i.e., just to the left of support B)
(b) x = 5.0+ ft (i.e., just to the right of support B)
(c) x = 19.5 ft
(d) x = 20.5- ft (i.e., just to the left of support C)
Note that x = 0 at point A. When entering your answers, use the shear-force sign convention detailed in Section 7.2.
Answers:
(a) V=
kips
(b) V=
kips
(c) V-
i
kips
(d) V =
i
kips
Determine the bending moment acting at each of the following locations:
(a) x = 5.0 ft (i.e., at support B)
(b) x = 19.5 ft
Note that x = 0 at point A. When entering your answers, use the bending-moment sign convention detailed in Section 7.2.
Answers:
(a) M =
i
kips-ft
(b) М-
i
kips-ft
Use your shear-force and bending-moment diagrams to determine the maximum positive bending moment, Mmax, pos the
maximum negative bending moment, Mmax, neg and their respective locations, Xmax, pos and Xmax, neg. Use the bending-moment sign
convention detailed in Section 7.2. The maximum negative bending moment is the negative moment with the largest absolute
value. Enter the maximum negative bending moment as a negative value.
Answers:
Mmax, pos=
kips-ft,, Xmax, pos
i
ft
Mmax, neg
kips-ft,
i
Xmax, neg
ft
Transcribed Image Text:(a) x = 5.0- ft (i.e., just to the left of support B) (b) x = 5.0+ ft (i.e., just to the right of support B) (c) x = 19.5 ft (d) x = 20.5- ft (i.e., just to the left of support C) Note that x = 0 at point A. When entering your answers, use the shear-force sign convention detailed in Section 7.2. Answers: (a) V= kips (b) V= kips (c) V- i kips (d) V = i kips Determine the bending moment acting at each of the following locations: (a) x = 5.0 ft (i.e., at support B) (b) x = 19.5 ft Note that x = 0 at point A. When entering your answers, use the bending-moment sign convention detailed in Section 7.2. Answers: (a) M = i kips-ft (b) М- i kips-ft Use your shear-force and bending-moment diagrams to determine the maximum positive bending moment, Mmax, pos the maximum negative bending moment, Mmax, neg and their respective locations, Xmax, pos and Xmax, neg. Use the bending-moment sign convention detailed in Section 7.2. The maximum negative bending moment is the negative moment with the largest absolute value. Enter the maximum negative bending moment as a negative value. Answers: Mmax, pos= kips-ft,, Xmax, pos i ft Mmax, neg kips-ft, i Xmax, neg ft
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