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For the two signals x(t) and h(t) given by: x(t) 1 0.5 0 -6-5-4-3-2-10123456 t(s) the convolution: 1 €0.5 0 -6-5-4-3-2-10123456 t (s) y(t) = x(t) ⋆ h(t)

For the two signals x(t) and h(t) given by: x(t) 1 0.5 0 -6-5-4-3-2-10123456 t(s) the convolution: 1 €0.5 0 -6-5-4-3-2-10123456 t (s) y(t) = x(t) ⋆ h(t)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Please explain very thoroughly. I am confused as to why the graph starts increasing at 1 instead of zero. 

I think I might have done the shifting part wrong. Thanks

For the two signals x(t) and h(t) given by: x(t) 1 0 -6-5-4-3-2-10123456 t(s) the convolution: h(t) 1 0 -6-5-4-3-2-10123456 t (s) y(t) = x(t) ⋆ h(t)
Transcribed Image Text:For the two signals x(t) and h(t) given by: x(t) 1 0 -6-5-4-3-2-10123456 t(s) the convolution: h(t) 1 0 -6-5-4-3-2-10123456 t (s) y(t) = x(t) ⋆ h(t)
y(t) 1 0.5 0 -6-5-4-3-2-10123456 t (s)
Transcribed Image Text:y(t) 1 0.5 0 -6-5-4-3-2-10123456 t (s)
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