Asked Jan 17, 2019

four numbers have the sum of 9900. the second exceeds the first by 1/7 of the first. the third exceeds the sum of the first two by 30. the fourth exceeds the sum of the first by 300. find the four numbers.


Expert Answer

Step 1

Let a,b,c, and d respectively represent the first four numbers.

Given four numbers have a sum of 9900.i.e.,

Step 2

The second exceeds the first by one-seventh of the first.i.e.,

Step 3

The third exceeds the sum of the...


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