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Free fall An object in free fall may be modeled by assuming that the only forces at work are the gravitational force and resistance (friction due to the medium in which the object falls). By New- ton's second law (mass X acceleration = the sum of the external forces), the velocity of the object satisfies the differential equation m . v'(t) = mg + f(v), mass acceleration external forces where f is a function that models the resistance and the positive direction is downward. One common assumption (often used for motion in air) is that f(v) = -kv², where k > 0 is a drag coefficient. a. Show that the equation can be written in the form v' (t) = g – av?, where a = k/m. b. For what (positive) value of v is v' (t) = 0? (This equilibrium solution is called the terminal velocity.) c. Find the solution of this separable equation assuming v(0) = 0 and 0 < v(t)? < g/a, for t = 0. d. Graph the solution found in part (c) with g = 9.8 m/s, m = 1 kg, and k = 0.1 kg/m, and verify that the terminal velocity agrees with the value found in part (b).

Free fall An object in free fall may be modeled by assuming that the only forces at work are the gravitational force and resistance (friction due to the medium in which the object falls). By New- ton's second law (mass X acceleration = the sum of the external forces), the velocity of the object satisfies the differential equation m . v'(t) = mg + f(v), mass acceleration external forces where f is a function that models the resistance and the positive direction is downward. One common assumption (often used for motion in air) is that f(v) = -kv², where k > 0 is a drag coefficient. a. Show that the equation can be written in the form v' (t) = g – av?, where a = k/m. b. For what (positive) value of v is v' (t) = 0? (This equilibrium solution is called the terminal velocity.) c. Find the solution of this separable equation assuming v(0) = 0 and 0 < v(t)? < g/a, for t = 0. d. Graph the solution found in part (c) with g = 9.8 m/s, m = 1 kg, and k = 0.1 kg/m, and verify that the terminal velocity agrees with the value found in part (b).

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Free fall An object in free fall may be modeled by assuming that the only forces at work are the gravitational force and resistance (friction due to the medium in which the object falls). By New- ton's second law (mass X acceleration = the sum of the external forces), the velocity of the object satisfies the differential equation m . v'(t) = mg + f(v), mass acceleration external forces where f is a function that models the resistance and the positive direction is downward. One common assumption (often used for motion in air) is that f(v) = -kv², where k > 0 is a drag coefficient. a. Show that the equation can be written in the form v' (t) = g – av?, where a = k/m. b. For what (positive) value of v is v' (t) = 0? (This equilibrium solution is called the terminal velocity.) c. Find the solution of this separable equation assuming v(0) = 0 and 0 < v(t)? < g/a, for t = 0. d. Graph the solution found in part (c) with g = 9.8 m/s, m = 1 kg, and k = 0.1 kg/m, and verify that the terminal velocity agrees with the value found in part (b).
Transcribed Image Text:Free fall An object in free fall may be modeled by assuming that the only forces at work are the gravitational force and resistance (friction due to the medium in which the object falls). By New- ton's second law (mass X acceleration = the sum of the external forces), the velocity of the object satisfies the differential equation m . v'(t) = mg + f(v), mass acceleration external forces where f is a function that models the resistance and the positive direction is downward. One common assumption (often used for motion in air) is that f(v) = -kv², where k > 0 is a drag coefficient. a. Show that the equation can be written in the form v' (t) = g – av?, where a = k/m. b. For what (positive) value of v is v' (t) = 0? (This equilibrium solution is called the terminal velocity.) c. Find the solution of this separable equation assuming v(0) = 0 and 0 < v(t)? < g/a, for t = 0. d. Graph the solution found in part (c) with g = 9.8 m/s, m = 1 kg, and k = 0.1 kg/m, and verify that the terminal velocity agrees with the value found in part (b).
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