From a tower of height yo a particle is projected vertically up with a velocity vo in free space (gravity free). The acceleration of particle at an instant is given as a = k (vxĀ), where v is instantaneous velocity vector and A is given as Ā=-(-k), where y is the y vertical coordinate of particle at that instant. (Take origin as foot of the tower) Answer the following questions. 14. The speed of particle as a function of time will be (A) vo + kt (C) Vo-y/t (B) Vo+ (y/t)-(1/2)at (D) Vo y Vo f Yo (0, 0)
From a tower of height yo a particle is projected vertically up with a velocity vo in free space (gravity free). The acceleration of particle at an instant is given as a = k (vxĀ), where v is instantaneous velocity vector and A is given as Ā=-(-k), where y is the y vertical coordinate of particle at that instant. (Take origin as foot of the tower) Answer the following questions. 14. The speed of particle as a function of time will be (A) vo + kt (C) Vo-y/t (B) Vo+ (y/t)-(1/2)at (D) Vo y Vo f Yo (0, 0)
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Transcribed Image Text:From a tower of height yo a particle is projected vertically up with a velocity vo in free
space (gravity free). The acceleration of particle at an instant is given as ā = k (v ×Ā),
where v is instantaneous velocity vector and A is given as A = (-k), where y is the
H
y
vertical coordinate of particle at that instant. (Take origin as foot of the tower)
Answer the following questions.
D 14.
The speed of particle as a function of time will be
(A) vo + kt
(C) Vo-y/t
15.
(B) vo+ (y/t)-(1/2)at
(D) Vo
The maximum height attain by the particle will be
(A) y = Yo(1+evo/Kc)
(C) y = Yo (1-evo/kc)
(B) y = Yo(1+e */v)
(D) y Yo (1-e-c/vo)
t
Yo
(0, 0)
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