From the differential equation dy = x2 dx, what is the equation of y in terms of x as the curve passes through (1, 1)?

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A: We have to solve

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Q: What is the general solution of the differential equation; y’ = 2x cos (x^2)

A: solution:-y'=2x cosx2solving the differential equation we getdydx=2x cosx2y=∫2x cosx2 dxlet x2=t2x…

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A: In this question, we have to find the differential equation by eliminating parameters.

Q: The Integrating Factor of the differential equation dy dr y = 14x? is x-14 25 e5z

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A: As per bartleby expert policy only one individual question is to be answered. Kindly repost…

Q: xydx + 2(x2 +2y)dy=D0; when x= 0, y= 1

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