Please help me answer this problem with a complete answer and show it on a bond paper and box the final answer. God bless and more power... sir/madamTake note: the example photo is just a guide to inlight your mind. EXAMPLE #2:The table below shows the laboratory results of the sieve analysis of a sample. The soil has a liquidlimit of 35% and plastic limit of 26%. Classify the soil according to AASHTO.CumulativeTotal mass retained - Cumulative mass retainedPercentPercent Passing =x 100%Mass Retained Mass RetainedAbove EachSieveDiameter (mm)Total mass retainedPassing(Percent Finer)Sieve No.(grams)4.7618.9618.96For Seive #4:492%237 – 18.96Percent Passing =x 100% = 92%82.3833,18 €52.1478%237102.0045.0397.1759%For Seive #8:237 - 52.14200.8454.51151.6836%Percent Passing =x 100% = 78%237400.4242.66194.3418%For Seive #10:237 – 97.17206.19x 100% = 59%600.2511.8513%Percent Passing =2371000.1494.74210.9311%For SNve #20:2000.0744.74215.679%237 – 151.68x 100% = 36%Percent Passing =237PAN21.332370%TOTAL=237 From the given data, shows a sieve analysis of soil samples A and B. Classify the soil according toAASHTO Method.Sieve No.Diameter (mm)Percent Passing (Percent Finer)Soil Sample ASoil Sample B4RIC4.7610010082.3890100102.007778200.845992400.425184600.2542791000.14935702000.0743363Characteristics of – 40 fractionLL4647PL2924

We need to find group symbol and Group index number based on the given data Since we are given %…

From the given data, shows a sieve analysis of soil samples A and B. Classify the soil according to AASHTO Method. Sieve No. Diameter (mm) Percent Passing (Percent Finer) Soil Sample A Soil Sample B 4 RIC 4.76 100 100 8 2.38 90 100 10 2.00 77 78 20 0.84 59 92 40 0.42 51 84 60 0.25 42 79 100 0.149 35 70 200 0.074 33 63 Characteristics of - 40 fraction LL 46 47 PL 29 24

From the given data, shows a sieve analysis of soil samples A and B. Classify the soil according to AASHTO Method. Sieve No. Diameter (mm) Percent Passing (Percent Finer) Soil Sample A Soil Sample B 4 RIC 4.76 100 100 8 2.38 90 100 10 2.00 77 78 20 0.84 59 92 40 0.42 51 84 60 0.25 42 79 100 0.149 35 70 200 0.074 33 63 Characteristics of - 40 fraction LL 46 47 PL 29 24

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The given data sohws a sieve analysis of a soild sample. Classify the soild using AASHTO Method. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 96 No. 8 2.380 80 No. 10 2.000 78 No.20 0.840 61 No.40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 46 PL 31
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41.) The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 96 No. 8 2.380 80 No. 10 2.000 78 No. 20 0.840 61 No. 40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 37 PL 25 A. A-2-4(0) B. None of these. C. A-2-5(0) D. A-2-6(0) E. A-2-7(0)
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