From the top of the building, a ball is thrown straight up with an initial velocity of 32 feet per second. The equation s = -16t2 + 32t + 48 gives the height s of the ball t seconds after it is thrown. Find the maximum height reached by the ball and the time it takes for the ball to hit the ground. height ft time sec

Elementary Algebra
17th Edition
ISBN:9780998625713
Author:Lynn Marecek, MaryAnne Anthony-Smith
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Chapter10: Quadratic Equations
Section10.4: Solve Applications Modeled By Quadratic Equations
Problem 159E: A bullet is fired straight up from a BB gun with initial velocity 1120 feet per second at an initial...
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From the top of the building, a ball is thrown straight up with an initial velocity of 32 feet per second. The equation
s = -16t2 + 32t + 48
gives the height s of the ball t seconds after it is thrown. Find the maximum height reached by the ball and the time it takes for the ball to hit the ground.
height
ft
time
sec
48 ft
Transcribed Image Text:From the top of the building, a ball is thrown straight up with an initial velocity of 32 feet per second. The equation s = -16t2 + 32t + 48 gives the height s of the ball t seconds after it is thrown. Find the maximum height reached by the ball and the time it takes for the ball to hit the ground. height ft time sec 48 ft
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