function f(x) = x as OLX 22 Expand the cosine series in sine series in 0 2x 42.
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- Find the Fourier series of the function f(x), of period 2π, defined by: f(x)=sinx if x∈[0,π]; f(x)=0 if x∈[π,2π] Graph the solution. Please be as clear as possible showing all the steps. Thank you.A periodic function is defined in one period interval as f(x) = sin(x), -pi/2<x<0. (a) Sketch f(x) over the interval -pi<x<pi (b) find the fourier series (c) find the value of the fourier series at x = pi (i do not understand how to get this please illustrate it)For fourier series of periodic function how is the first picture = 2nd picture? able to provide the derivation
- fomular f(x) =tanx/x and has a hole at x=0 prove algebricaly that it has a hole at x=0A periodic function is defined in one period interval as f(x) = sin(x), -pi/2<x<0. (a) Sketch f(x) over the interval -pi<x<pi (b) find the fourier series (c) find the value of the fourier series at x = pi For part(c) how can i solve for part(c) without looking at the sketch?f(x) is a periodic function with period 2π where the value of f(x) in the interval -π <x < π is : (in picture 1) Please Expansion f(x) using Fourier series!
- Using the table of Fourier series.( Need only handwritten solution please otherwise downvote)Urgent numerical method Calculate the value of f(x) = sinx cosx at ? = 0.1 using the 4th order derivative Taylor series. Compare your result with the value you calculated from the calculator.Find the force series of these functions and converging radius.