f(x) = 4x^2+5x+6 Use 5 long method for solution  Use 6-long method for checking of solution  Please refer to the image below for example

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
  1. f(x) = 4x^2+5x+6
  • Use 5 long method for solution 
  • Use 6-long method for checking of solution 
  • Please refer to the image below for example 
Example
3. y = -x-5
d
dx
→y'=-1-0
→y' = -1
Differentiate the following functions:
4. f(x) = x³
du dv
dx dx
dx
dx
→ (u²) = nun-1 du
→ f'(x) = (3)(x³-1)
→ f'(x) = 3x²
6 long method for checking of solution
(u±v) = ±
Transcribed Image Text:Example 3. y = -x-5 d dx →y'=-1-0 →y' = -1 Differentiate the following functions: 4. f(x) = x³ du dv dx dx dx dx → (u²) = nun-1 du → f'(x) = (3)(x³-1) → f'(x) = 3x² 6 long method for checking of solution (u±v) = ±
Example
1. f(x) = x - 5
f(x + h) = f(x)
f'(x) = lim
= lim! h
lim
= lim
(x+h)-5-(x −5)
x+h-5-x+5
h
x-x+h-5+5
h
lim
h-oh
= lim 1
h→0
Therefore f'(x) = 1
5 long method
Transcribed Image Text:Example 1. f(x) = x - 5 f(x + h) = f(x) f'(x) = lim = lim! h lim = lim (x+h)-5-(x −5) x+h-5-x+5 h x-x+h-5+5 h lim h-oh = lim 1 h→0 Therefore f'(x) = 1 5 long method
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