fx (x, y)=-2xety-x²-y- fxx (x, y)=-2e4y¬x²-y² + 4x²e4y¬x²¬y? fy (x, y)=(4 – 2y)e+y¬x²-y² fyy (x, y)=-8ye4y-r²-y* _ 2e+y=x²-y² + 4y²e+y=x²- + 4y²e%v=x²-

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How did he get
the derivative?
f(x, y)=-2xe*ーx?-y
fxx (x, y)=-2e4v-r²-y²
+ 4x?e+y¬x²¬y²
fy (x, y)=(4 – 2y)e4y¬x²-y²
fyy (x, y)=-8ye4y=x²-y² – 2e4y-x²-y² + 4y²e4y¬x²-y²
fxy (x, y)=-2x (4 – 2y)e4y¬x²-y²
Now, find the stationary points.
-2xeyーxーy=0
メ=0 : ードード +0|
(4 – 2y)e+y¬x²¬y° =0
y=2
Transcribed Image Text:How did he get the derivative? f(x, y)=-2xe*ーx?-y fxx (x, y)=-2e4v-r²-y² + 4x?e+y¬x²¬y² fy (x, y)=(4 – 2y)e4y¬x²-y² fyy (x, y)=-8ye4y=x²-y² – 2e4y-x²-y² + 4y²e4y¬x²-y² fxy (x, y)=-2x (4 – 2y)e4y¬x²-y² Now, find the stationary points. -2xeyーxーy=0 メ=0 : ードード +0| (4 – 2y)e+y¬x²¬y° =0 y=2
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