f(x)=0 for x EQ and f(x)=x otherwise. We can conclude f is not integrable on [-1,1] sim

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 32E
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Question 14
Indicate of the following statement is TRUE or FALSE. Briefly justify your response with an explanation or a counterexample.
Set f(x)=0 for x EQ and f(x)= x otherwise. We can conclude f is not integrable on [-1,1] since / is not continuous anywhere in [-1,1].
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Transcribed Image Text:Question 14 Indicate of the following statement is TRUE or FALSE. Briefly justify your response with an explanation or a counterexample. Set f(x)=0 for x EQ and f(x)= x otherwise. We can conclude f is not integrable on [-1,1] since / is not continuous anywhere in [-1,1]. For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph Open Sans sa... V 10pt 111 A N M I. % 0
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