fx(x)= Stashq otherwise 0 Find pdf of Z=X+Y fylg1= 1 тосуслу 0 10therwise
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looked at markscheme but have no clue whats going. Can you solve this and explain how to find the limits and why z was split into between 0 and 1 and 1 and 2 in the markscheme
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- Find the absolute maximum and minimum values of the function f(x, y) =2x2− 4x + 3y2 + 2 on the region R = {(x, y)|(x − 1)2 + y2 ≤ 1}. This uses Lagrange multipliers and the second derivative test to try and find the local extrema of these functions, but I don't know how to isolate one specific variable to solve this.The number of defects on the front side (X) of a wooden panel and the number of defectsa on the rear side (Y) of the panel are under study. Suppose that the joint pmf of X and Y is modeled as fxy(x,y)=c(x+y), x= 1,2,3 and y=1,2,3. Determine the value of c.A ruptured pipe produces a circular oil slick that is y meters thick at a distance x meters from the rupture. It is difficult to directly measure the thickness of the slick at the source (where x=0), but for x>0, it is found that y=0.5(x2+3x)/x3+x2+4x. assuming that the oil slick is continuously distributed, how thick would you expect it to be at the source?
- J(X) = -3|X – 5| + 21. Why does J(X) have a critical point at X = 5? Explain.2. Why does J(X) not have a horizontal tangent line at X = 5? Explain.3. Does J(X) have a local maximum at X = 5? Explain.The functions f(x, y) = x 2 + y 2 and g(x, y) = x 2 - y 2 both have acritical point at (0, 0). How is the behavior of the two functions at the critical point different?For what values of the constant k does the Second Derivative Test guarantee that ƒ(x, y) = x2 + kxy + y2 will have a saddle point at (0, 0)? A local minimum at (0, 0)? For what values of k is the Second Derivative Test inconclusive? Give reasons for your answers.
- A manufacturer's marginal revenue function is: dr = 25 .- - q— 0.3q3. If r is in omani rials, find the increase in the manufacturer's total revenue if q production is increased from 10 to 25 units. 2 0 3 (b)If f f(x)dx = 6 and f f(x)dx = 3, find f f(x)dx. 0 3 2find the solution to the boundary value problem second derivative - 6*first derivative + 5y = 0. where y(0) = 6 and y(1) = 4 the solution is y = ?f(x,y) = x6-2xy-7y2 f(x,y) =(x6-6) (2y+6) f(x,y) =squared root of (2x2+y2) f(x,y) = e(x+y+4) f(x,y) = e(8*x*y) ln(3y)
