G. "I can use the remainder and factor theorems to help factor polynomial equations of degree 3 or 4." 1. x²-x-x-10 by *-2 2. *²¹-28x-41 3. 2x²-3x²-8x-3 by x²-3x-7 x-2x - 5x²-x-10 x'-2₁² ↓ ↓ -3x²-x + -3x²+6x -7x-10 -7x+14 -24 P(2)= Now, for P(x) try P(x)=x²-5x²-x-10 x = 2 1-4x-12 x+ 4x + 0x - 28-41 x² + 4x² by - 4x² -28.r -4x²-16.x -12x-41 - 12.x - 48 7 x+4 Now, for P(x) try = -4 P(x) = x³ - 28x-41 P(-4)= x-2x-3 2x+12x²-3x²-8x-3 2x¹+x² ↓ ↓ -4.² -8.x -4.x² - 2x -6x -3 -6.x-3 0 Now, for P(x) try*=-1 P(x) = 2x¹³ - 3x²-8x-3 P(-) =
G. "I can use the remainder and factor theorems to help factor polynomial equations of degree 3 or 4." 1. x²-x-x-10 by *-2 2. *²¹-28x-41 3. 2x²-3x²-8x-3 by x²-3x-7 x-2x - 5x²-x-10 x'-2₁² ↓ ↓ -3x²-x + -3x²+6x -7x-10 -7x+14 -24 P(2)= Now, for P(x) try P(x)=x²-5x²-x-10 x = 2 1-4x-12 x+ 4x + 0x - 28-41 x² + 4x² by - 4x² -28.r -4x²-16.x -12x-41 - 12.x - 48 7 x+4 Now, for P(x) try = -4 P(x) = x³ - 28x-41 P(-4)= x-2x-3 2x+12x²-3x²-8x-3 2x¹+x² ↓ ↓ -4.² -8.x -4.x² - 2x -6x -3 -6.x-3 0 Now, for P(x) try*=-1 P(x) = 2x¹³ - 3x²-8x-3 P(-) =
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter8: Polynomials
Section8.6: Factoring Quadratic Trinomials
Problem 61PFA
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