Geometric series can be found by transforming f(x)= to series form using 1 4 Maclaurin's series to get 1-X = E=0x² = 1 + x + x² + x³ + x¹ + 1) Why this series diverges at x = 4 while the function is defined. 2) Why this series diverges at x = -4 while the function is defined.
Geometric series can be found by transforming f(x)= to series form using 1 4 Maclaurin's series to get 1-X = E=0x² = 1 + x + x² + x³ + x¹ + 1) Why this series diverges at x = 4 while the function is defined. 2) Why this series diverges at x = -4 while the function is defined.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
Problem 3RE
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Question
![Geometric series can be found by transforming f(x)= to series form using
1
4
Maclaurin's series to get
1-X
= E=0x² = 1 + x + x² + x³ + x¹ +
1) Why this series diverges at x = 4 while the function is defined.
2) Why this series diverges at x = -4 while the function is defined.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F666dcfe9-15e5-4177-9c33-86e4aba92fae%2F84d12047-c5a1-4c05-b015-0813b8c4fad6%2Fa9058ds_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Geometric series can be found by transforming f(x)= to series form using
1
4
Maclaurin's series to get
1-X
= E=0x² = 1 + x + x² + x³ + x¹ +
1) Why this series diverges at x = 4 while the function is defined.
2) Why this series diverges at x = -4 while the function is defined.
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