Give asymptotically tight upper and lower bounds for T (n) in each of the following algorithmic recurrences. Justify your answers. A. T(n) = T(7n/10) + n B. T(n) = 16T(n/4) + nº C. T(n) = 2T(n/4) + √√n
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- for the given 1,2,3 find the recurrences - the closed-form expression for n. 1) S(0) = 6 for n = 0 S(n) = S(n-1) + 2 for n = 1, 2, 3, ... 2) T(1) = 2 for n = 1 T(n) = 2T(n-1) + 4 for n = 2, 3, 4, … 3) Q(1) = c for n = 1 Q(n) = Q(n/2) + 2n for n = 2, 4, 8, …I am not an engineering student. Grateful for your detailed explanation.Give tight asymptotic bounds for the following recurrences. • T(n) = 4T(n/2) + n 3 − 1. • T(n) = 8T(n/2) + n 2 . • T(n) = 6T(n/3) + n. • T(n) = T( √ n) + 1Give asymptotic upper and lower bounds for T(n) in each of the following recurrences. Assume that T (n) is constant for n ≤ 3. Make your bounds as tight as possible, and justify your answers T (n) = 7T (n/2) + n3
- Give asymptotic upper and lower bounds for T(n) in each of the following recurrences. Assume that T (n) is constant for n ≤ 3. Make your bounds as tight as possible, and justify your answers (you can use any of the methods we discussed in class). 1) T (n) = 7T (n/2) + n3 2) T(n)=T(n/2)+lgn 3) T (n) = 3T (n/5) + log2 nLet T(n)T(n) be defined by the first-order linear recurrenceT(n)=5T(n−1)+3T(n)=5T(n−1)+3Suppose it is given that T(2)=cT(2)=c. Compute T(0)T(0) by iterating backwards and express your answer in terms of cc.T(0)T(0) =What are the theta values for the recurrences given below in Q1-Q3? (Show your work in details) 1. T(n)=5T(n/5) + n^2 (2) T(n) = 3T(n-1) +1
- (a) For each of the following recurrences, give an expression for theruntime T (n) if the recurrence can be solved with the Master Theorem.Otherwise, indicate that the Master Theorem does not apply.(i) T (n) = T (n/2) + T(n/2) + T(n/2) + n2(ii) T (n) = 0.5T (n/2)+ 1/n(iii) T (n) = 3T (n/3) + n(iv) T (n) = 4T (n/2) + nlognSolve the following recurrences exactly:(a) T(1) = 8, and for all n ≥ 2, T(n) = 3T(n − 1) + 15.(b) T(1) = 1, and for all n ≥ 2, T(n) = 2T(n/2) + 6n − 1 (n is a power of 2)Please written by computer source Given two strings x1…xn, y1…ym find the length of their longest common subsequence, that is, the largest k for which there exist indices i1<…<ik and j1<=<jk such that xi1…xik…=yj1=yjk. Show how to do this in time O(nm) and find its space complexity.
- Using the code in the picture (Phyton 3): Find the Recurrence relation for foo(a, b) when b > 0 (Follow the format) T(n) = ___ T ( ___ / ___ ) + O ( ___ ) What is the worst-case time complexity of foo(a, b)? What is the worst-case auxiliary space complexity of foo(a,b)?Find a bound for each recurrence below using Master Theorem:(a) T(n) = 3T(n=2) + n2(b) T(n) = 2T(n=4) + n0:49(c) T(n) = 3T(n=3) + n=2course: Introduction to Algorithms Give asymptotic upper and lower bounds for T(n) in each of the following recurrences. Assume that T(n) is constant for n ≤ 10. Make your bounds as tight as possible, and justify your answers. a. T (n) = 2T (n) + n log n