Give Regular expression that represent the following sets of strings over {a,b} 1. L1 = At most three occurrences of b. 2. L2 = {a2n+1 | n > 0}
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Give Regular expression that represent the following sets of strings over {a,b}
1. L1 = At most three occurrences of b.
2. L2 = {a2n+1 | n > 0}
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- Write a regular expression for the set of strings over the alphabet {a, b} that have at least one a andat least one b. For example, aaaba and bbaba are strings in the set, but aaaa and bbb are not.Draw a DFA over the alphabet {a,b,c}that only accepts strings with no c's and an even number of a's, or an odd number of c's and an odd number of b's. For example, it should accept aa, aba, abbabaa, cbacabcb, cbcca, and abc but not aca, bacc, or aaa.Build a DFA that accepts the set of string over {a,b} in which the number of a’s is divisible by three.
- Write programs with these input and output Given positive integers m and n, find the number of ontofunctions from a set with m elements to a set with n elements.With simply the at, length, and substr string methods and the + (concatenate) operator, construct a function that accepts a string s, a start position p, and a length l and returns a subset of s without the characters starting at position p. Strings begin at 0. (“abcdefghijk”, 2, 4) yields “abghijk”.Show L = { w | w is an element of {0, 1, 2}* and (the number of 0s in w ≥ the number of 1s in w) and ((the number of 0s + the number of 1s in w) divides the number of 2s in w) } is not context free. You should assume that p is the pumping length and for any string s in L with |s| ≥ p, s can be broken into 5 pieces, s = uvxyz.
- Write a program in c language to analyze the letter frequencies in a block of text. Ignore case (upper and lower count the same). It should count the number of times each letter appears in the text, the number of times each pair of letters appears, and the number of times each sequence of 3 letters appears. Your program should sort the counts of single letters, pairs of letters (bigrams), and triples of letters (trigrams), then print the non-zero values in decreasing order. For single letters, print all non-zero values; for bigrams and trigrams, print the first 30 non-zero values.(monoalphabetic substitution ciphers)write a program in C++ Fibonacci NumbersThe Fibonacci numbers are defined by the sequencef1 = 1f2 = 1fn = fn-1 + fn-2Reformulate that as5t1 = 1;t2 = 1;nextTerm = t1 + t2;After that, discard t1, which is no longer needed, and set t1 to t2 and t2 to nextTerm.Repeat fnew an appropriate number of times. Implement a program that given a numberN, prints the first N numbers in the Fibonacci sequence. For example, given the number8, the output isThe Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21Implement the following function in C programming language that get a string, and compute an array of non-empty tokens of the string containing only lower-case letters. For example: ● For a string "abc EFaG hi", the list of tokens with only lower-case letters is ["abc", "hi"]. ● For a string "ab 12 ef hi ", the list of such tokens is ["ab","ef","hi"]. ● For a string "abc 12EFG hi ", the list of such tokens is ["ab","hi"]. ● For a string " abc ", the list of such tokens is ["abc"]. ● For a string "+*abc!! B" the list of such tokens is empty.That is, we break the string using the spaces as delimiters (ascii value 32), and look only at the tokens with lower-case letters only . The function get_tokens gets a string str, and returns the array with the tokens containing only lower-case letters in the correct order. The length of the array should be the number of tokens, computed in count_tokens. char** get_tokens(const char* str); For example:● get_tokens("abcEFaG…
- solve in C please. Implement the following two functions that get a string, and compute an array of non-emptytokens of the string containing only lower-case letters. For example:● For a string "abc EFaG hi", the list of tokens with only lower-case letters is ["abc", "hi"].● For a string "ab 12 ef hi ", the list of such tokens is ["ab","ef","hi"].● For a string "abc 12EFG hi ", the list of such tokens is ["abc","hi"].● For a string " abc ", the list of such tokens is ["abc"].● For a string "+*abc!! B" the list of such tokens is empty.That is, we break the string using the spaces as delimiters (ascii value 32), and look only at thetokens with lower-case letters only .1. The function count_tokens gets a string str, and returns the number ofsuch tokens.int count_tokens(const char* str);For example● count_tokens("abc EFaG hi") needs to return 2.● count_tokens("ab 12 ef hi") needs to return 3.● count_tokens("ab12ef+") needs to return 0.2. The function get_tokens gets a string str, and…In Python, The function concatAltChars takes a string parameter s and a boolean parameter even; the function concatenates together either the even-position characters of s or the odd-position characters of s, depending on whether even is True, or False, respectively. The accumulated string is returned. For example, the even-indexed characters of "HANOVER" are at indexes 0, 2, 4, and 6: H N V R. So, concatAltChars("HANOVER", True) returns the string result "HNVR". But concatAltChars("HANOVER", False) returns the string result "AOE". For example: Test Result s = "goldfinches" print(concatAltChars(s, True)) glfnhs s = "A" print(concatAltChars(s, True)) A s = "A" print(concatAltChars(s, False))Write a function that takes a string s, a start position p, and a length l and returns a subset of s with the characters starting at position p deleted, using just the at, length, and substr string methods and the + (concatenate) operator. Sequences start at 0. ("abcdefghijk", 2, 4) yields "abghijk".