Given 16-bit instructions, is it possible to use expanding opcodes to allow the follow- ing to be encoded assuming we have a total of 32 registers? If so, show the encoding. If not, explain why is it not possible. • 60 instructions with two register operands • 30 instructions with one register operand
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- Two 1-bit values generate a 1 result value when a(n) _____ instruction is executed. All other input pairs generate a 0 result value.Given 16-bit instructions, is it possible to use expanding opcodes to allow the following to be encoded assuming we have a total of 32 registers? If so, show the encoding. If not, explain why it is not possible. 60 instructions with 2 register operands3 instructions with one 10-bit address30 instructions with 1 register operands26 instructions with zero operandsGiven 16-bit instructions, is it possible to use expanding opcodes to allow the following to be encoded assuming we have a total of 32 registers? If so, show the encoding. If not, explain why is it not possible.Q. 3 instructions with one 10-bit address
- Given 16-bit instructions, is it possible to use expanding opcodes to allow the following to be encoded assuming we have a total of 32 registers? If so, show the encoding. If not, explain why is it not possible.Q. 60 instructions with two register operandsGiven 16-bit instructions, is it possible to use expanding opcodes to allow the following to be encoded assuming we have a total of 32 registers? If so, show the encoding. If not, explain why is it not possible.Q. 30 instructions with one register operandGiven 16-bit instructions, is it possible to use expanding opcodes to allow the following to be encoded assuming we have a total of 32 registers? If so, show the encoding. If not, explain why is it not possible.Q. 26 instructions with zero operands
- A digital computer has a memory unit with 24 bits per word. The instruction set consists of 150 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory.Q.) What is the largest unsigned binary number that can be accommodated in one word of memory?The 8-bit register AR, BR, CR, and DR initially have the following values: [5]AR = 11010010; BR = 11111111; CR = 10101001; DR = 10101010Determine the 8-bit values in each register after the execution of the following sequence ofmicrooperations.AR AR + BR Add BR + ARCR CR AND DR, BR BR + 1 AND DR to CR, Increment BRAR AR - CR Subtract CR from AR3. If we have an 8 bit microcontroller that has 4kB of instruction memory starting at address 0x0000, and 2kB of data memory immediately above that, what is the next available byte in our address map?
- Compare 0-, 1-, 2-, and 3-address machines by writing programs to computeX = (A x B + C) / (D − E × B)for each of the four machines. The instructions available for use are as follows: M is a 16-bit memory address, and X, Y, and Z are either 16-bit addresses or 4-bit registers. The0-address machine uses a stack, the 1-address machine uses an accumulator, and the other two have16 registers and instructions operating on all combinations of memory locations and registers. SUB X,Y subtracts Y from X and SUB X, Y, Z subtracts Z from Y and puts the result in X. With 8-bit opcodesand instruction lengths that are multiples of 4 bits, how many bits does each machine need to computeX?Assemble the machine codes of the MIPS instructions (all the way to HEX values).Instruction 1: sub $s3, $t2, $v1 Instruction 2: sw $t3, -16($s1) a)Show all the bit fields of instruction 1 & 2. b)Type the machine code of instruction 1&2 in HEX.The 8-bit registers AR, BR, CR, and DR initially have the following values: AR= 11010010, BR= 11100011, CR= 10111001 , DR= 10101011 Determine the 8-bit values in each register after the execution of the following sequence of microoperations. AR <-AR + BR CR <- CR ^ DR, BR <- CR + 1 AR <-AR – CR