Given: [(4x + 3)²D² - 12(4x + 3)D +64]y = 16[(4x + 3)² sec² (In|4x +31)], transform it to z. A. 64(D²D+)y = 16e2sec²z B. (D2 - 4D + 4)y= ²² sec²z C. 64(D²D+)y= 16e2 sec²2z D. (D² - 4D + 4)y= ²² sec²2z

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