Given A = {1,2, 3, 4} and B = {x,y , z}. Let R be the following relation from A to B: R = {(1,y),(1,z),(3,y),(4,x),(4,z)} Find the inverse relation R-1 of R.

Q: 2 T= {(x, y): y = x2+4

A: The given relation,   T=x,y: y=2x2+4

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A: Solution:Given ƒ(x, y) = 50 + 4x - 5y + x2 + y2 + xyand ƒx( x, y)  =  0 and ƒy ( x, y) = 0

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A: Now,

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A: Given that:

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A: Answer is 40 Explanation is given below...

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A: We wil find the value of r'(1) as following .

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A: To find out r'(1).

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A: Given rx=fghx, where h1=5, g5=4, h'1=3, g'5=3, and f'4=5. Then we have to find r'1.

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