Given a array of integer and you have to count the absolute unique element from that. In java. Array is [2,6, 93,8,8,2,26,72,72 ,-72,-2 -2,27,82,6,26,25,9290,725,73,6,93,8,2,208,83,636]
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![Given a array of integer and you have to count the
absolute unique element from that.
In java.
Array is [2,6, 93,8,8,2,26,72,72,-72,-2
-2,27,82,6,26,25,9290,725,73,6,93,8,2,208,83,636]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc82a6daa-b062-49f8-bb93-5d9bdbf4a849%2F4f58a2c2-080c-4d6d-8e62-cc47d7f68f17%2F6n179qv_processed.jpeg&w=3840&q=75)
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- Write a program in java that randomly fills in 0s and 1s into an n-by-n matrix, prints the matrix, and finds the rows and columns with the most 1s. (Hint: Use two ArrayLists to store the row and column indices with the most 1s.)Given an ArrayList of integers, return an ArrayList where all the odds are before the evens in the order that they occur. public ArrayList<Integer> solution(ArrayList<Integer> nums) {ArrayList<Integer> finalList = new ArrayList<>();int index = 0;for (int i = 0; i < nums.size(); i++) {if (nums.get(i) % 2 == 1) {finalList.add(index, nums.get(i));index++;} elsefinalList.add(nums.get(i));}return finalList;} This is my failing code. for [1.-3.3] where [1,3,-3] is being returnedFOR JAVA Write a method that takes an integer array and returns the difference between the sum of even indexed elements and the sum of odd indexed elements in that array.
- Write method findZero, as started below. findZero should return the index of the first element of array A that contains the value zero, starting from position 0 up through position pos. If no element of A from position 0 to position pos contains the value zero, then findZero should return –1. For example:(in java) Array (A) Position (pos) Value returned by findZero(A, pos) 1 0 2 5 6 0 -1 1 0 2 5 6 1 1 1 0 2 5 6 2 1 1 0 2 0 6 2 1 1 0 2 0 6 4 1 1 2 3 4 5 4 -1 Complete method findZero below. Assume that it is called only with values that satisfy its assumptions as stated below. // Description: Returns smallest index k // such that (0 <= k <= pos) and (A[k] == 0) // Assumptions: 0 <= pos < A.length public int findZero(int[] A, int pos) {Write a Java program to find continuous sub array of the given array whose sum is equal to a given number. For example, If {12, 5, 31, 9, 21, 8} is the given array and 45 is the given number, then you have to find continuous sub array in this array such that whose elements add up to 45. In this case, {5, 31, 9} is such sub array whose elements add up to 45.Write a JAVA program to find the unique element which is present only once in the given array. All the remaining elements are repeated twice in the array. int []a = {2, 14, 6, 22, 2, 34, 22, 8, 6, 14, 8}; Use constant space and linear time.
- Write a Java code about a 2D array by declaring the month of January 2022.# the method take another circular array and returns a linear array containing the common elements between the two circular arrays. def intersection(self, c2): # To Do print("==========Test 10==========") lin_arr9 = [10, 20, 30, 40, 50, None, None, None] c10 = CircularArray(lin_arr9, 5, 5) c10.printFullLinear() # This should print: 40, 50, None, None, None, 10, 20, 30 lin_arr10 = [5, 40, 15, 25, 10, 20, 5, None, None, None, None, None] c11 = CircularArray(lin_arr10, 8, 7) c11.printFullLinear() # This should print: 10, 20, 5, None, None, None, None, None, 5, 40, 15, 25 output = c10.intersection(c11) print(output) # This should print: [10, 20, 40]Take an array of length n where all the numbers are nonnegative and unique. Find the element inthe array possessing the highest value. Split the element into two parts where the first part containsthe next highest value in the array and the second part holds the required additive entity to get thehighest value. Return the array index value. Consider the negative numbers as well.Input: [4, 8, 6, 3, 2]Output: [4, 6, 2, 6, 3, 2]
- Write a java method that finds the minimum of each arrayWrite a java program to find the 2nd largest number in the array and explain program withcomments.For this exercise, you need to shift all the elements in the array one space to the right (increase the index of the element by 1). The last element will wrap around and become the new first element. For example, given: moveUp({"first", "second", "third", "fourth"}); You would return: {"fourth", "first", "second", "third"} in java