Given a binary tree, write a function that prints the binary search tree’s nodes level by level, for example the following tree will have the following output statement: 1, 2, 3, 4, 5
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Given a binary tree, write a function that prints the binary search tree’s nodes level by level, for example the following tree will have the following output statement:
1, 2, 3, 4, 5
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- c++ programming Complete all these 2 methods for the node Node methods •int get_depth(): Returns the depth of the node. •int get_height(): Returns the height of the node. Initial code to be completed:struct node { node* parent; node* right; node* left; int element; int get_depth() { return 0; } int get_height() { return 0; }};1.Assume some Node class with info link fields . Complete this method in class List that returns a reference to the node containing the data item in the argument findThis, Assume that findThis is in the list public class list { protected Node head ; Protected int size ; Public Node find (char find this) { Node curr = head; while(curr != null) { if(curr.info == findThis) return curr; curr = curr.link; } return -1; } }C++ PROGRAMMING Please implement these 2 methods for the node where: •int get_depth(): Returns the depth of the node. •int get_height(): Returns the height of the node. Initial code to be completed: Note: Do not add new member variables for the depth and height. struct node { node* parent; node* right; node* left; int element; int get_depth() { return 0; } int get_height() { return 0; }};
- What happens when a programmer attempts to access a node's data fields when the node variable refers to None? How do you guard against it? *PYTHONstarter code: in java pls and thank you! public class LinkedList { private Node head; private Node tail; public void add(String item) { Node newItem = new Node(item); // handles the case where the new item // is the only thing in the list if (head == null) { head = newItem; tail = newItem; return; } tail.next = newItem; tail = newItem; } public void print() { Node current = head; while (current != null) { System.out.println(current.item); current = current.next; } } public void printWithSkips() { // TODO your code here } class Node { String item; Node next; public Node(String item) { this.item = item; this.next = null; } } } and public class Driver { public static void…Please fill in the code gaps if possible. This problem has been giving me trouble. Any help is appreciated. public class Node { private String element; // we assume elements are character strings private Node next; /* Creates a node with the given element and next node. */ public Node(String s, Node n) { //fill in body } /* Returns the element of this node. */ public String getElement() { //fill in body } /* Returns the next node of this node. */ public Node getNext() { //fill in body } // Modifier methods: /* Sets the element of this node. */ public void setElement(String newElem) { //fill in body } /* Sets the next node of this node. */ public void setNext(Node newNext) { //fill in body } }
- Public class DLL{ public DLLNode first; public DLLNode last; public DLL() {this.first=Null; this.last=Null;} Public void Display() {if (first==Null) {s.o.p(“ the list is empty”);} else {for (DLLNode curr=first; curr!=Null; curr=curr.succ) {System.out.println(“the element is”+ curr.element); }} Public void AddBegining(DLLNode Node) {Node.succ=first; First.prev=Node First=Node; Node.prev=Null; if(first ==null && last==null) Last=node; } Public void Append(DLLNode Node) {Node.succ=Null; if(first==Null) {first=Node; Node.prev=Null} Public void insetAfter(int obj, DLLNode Node) {DLLNode curr=first; while((curr!=Null)&&( curr.element!=obj)) { curr=curr.succ; } If(curr.element==obj) {Node.succ=curr.succ; Curr.succ.prev=Node; Curr.succ=Node; Node.prev=curr;} Else System.out.println(“the element doesn’t exist”); Public void delete(DLLNode del) { if(first==Null) {System.out.println(“the list is empty”); } Else if(del==first)…1. Struct (Optional: 1 point)1) Use the following abstract data type called Rectangle to get the length and width from the user. 2) Display the length, width, area, perimeter, and whether the rectangle is a square.struct Rectangle{float length;float width;float area;float perimeter;};2. Linked List (Optional: 1 point)Modify the following program to make a node containing data values of int, char, and string:#include <iostream>using namespace std;struct Node { int data; struct Node *next; };struct Node* head = nullptr; //or NULL or 0;void insert(int new_data) { struct Node* new_node = (struct Node*) new (struct Node); new_node->data = new_data; new_node->next = head; head = new_node; } void display() { struct Node* ptr;ptr = head;while (ptr != NULL) { cout<< ptr->data <<" "; ptr = ptr->next; } } int main() { insert(2);display(); return 0; } 1) Create a linked list of ten nodes (each node contains the three types of data values). 2) Display the data values…typedef struct node{int data;struct node *left,*right;}BST;The node structure of BST is shown above. Please design an efficient algorithm to return the maximum keyword value in BST. Completion function: int findmax (BST *T)
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