Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values. For example: Input: 5 Output: True because the binary representation of 5 is: 101. Input: 7 Output: False because the binary representation of 7 is: 111. Input: 11 Output: False because the binary representation of 11 is: 1011. Input: 10 Output: True because The binary representation of 10 is: 1010.
Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values. For example: Input: 5 Output: True because the binary representation of 5 is: 101. Input: 7 Output: False because the binary representation of 7 is: 111. Input: 11 Output: False because the binary representation of 11 is: 1011. Input: 10 Output: True because The binary representation of 10 is: 1010.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Given a positive integer, check whether it has alternating bits: namely, | |
if two adjacent bits will always have different values. | |
For example: | |
Input: 5 | |
Output: True because the binary representation of 5 is: 101. | |
Input: 7 | |
Output: False because the binary representation of 7 is: 111. | |
Input: 11 | |
Output: False because the binary representation of 11 is: 1011. | |
Input: 10 | |
Output: True because The binary representation of 10 is: 1010. | |
""" | |
# Time Complexity - O(number of bits in n) | |
def has_alternative_bit(n): | |
first_bit=0 | |
second_bit=0 | |
whilen: | |
first_bit=n&1 | |
ifn>>1:.
|
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