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Given a quadratic equation, write in standard form and then substitute the values of a, b, and c into the quadratic formula. Solve the equation by using the quadratic formula. 7x-9x-5=x-1 21. Subsitute a, b, and c into the quadratic C Choices for 21-30: formula. CF 22. Solve for x. 4+ V(-4) - 4(12)(9) A) x = 1,5/2 BD) x = -士- 2(12) 3 -4+ (4)-4(9)(-6) B) x = - 3+ V3 BE) x = x -x-6= 3x - 11x – 15 2(9) 23. Subsitute a, b, and c into the quadratic 4 formula. AOE -12+ /(12) - 4(4)(9) C) x = 3 CD) x : 2 2(4) 24. Solve for x. -12+ (12) - 4(6)(4) D) x = 9+V177 CE) x = 2(6) 12 4x-6+9x? = 0 9V(-9-4(6)(4) E) x = 3. V15 25. Subsitute a, b, and c into the quadratic ABC) x = 2(6) 12 formula. ACO 4±V(-4) - 4(9)(6) AB) x = 26. Solve for x. 2 ABD) x=- 2.

Given a quadratic equation, write in standard form and then substitute the values of a, b, and c into the quadratic formula. Solve the equation by using the quadratic formula. 7x-9x-5=x-1 21. Subsitute a, b, and c into the quadratic C Choices for 21-30: formula. CF 22. Solve for x. 4+ V(-4) - 4(12)(9) A) x = 1,5/2 BD) x = -士- 2(12) 3 -4+ (4)-4(9)(-6) B) x = - 3+ V3 BE) x = x -x-6= 3x - 11x – 15 2(9) 23. Subsitute a, b, and c into the quadratic 4 formula. AOE -12+ /(12) - 4(4)(9) C) x = 3 CD) x : 2 2(4) 24. Solve for x. -12+ (12) - 4(6)(4) D) x = 9+V177 CE) x = 2(6) 12 4x-6+9x? = 0 9V(-9-4(6)(4) E) x = 3. V15 25. Subsitute a, b, and c into the quadratic ABC) x = 2(6) 12 formula. ACO 4±V(-4) - 4(9)(6) AB) x = 26. Solve for x. 2 ABD) x=- 2.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.6: Solving Quadratic Equations By Using The Quadratic Formula
Problem 15CYU
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Given a quadratic equation, write in standard form and then substitute the values of a, b, and c into the quadratic formula. Solve the equation by using the quadratic formula. 7x -9x-5=x -1 21. Subsitute a, b, and c into the quadratic C Choices for 21-30: formula. CE 22. Solve for x. 4+ (-4)° – 4(12)(9) A) x = 1 BD) x ==+- 3 2(12) x -x-6= 3x-11x – 15 -4 + V(4) – 4(9)(-6) 3+ V3 BE) x = B) x = 2(9) 23. Subsitute a, b, and c into the quadratic 4 formula. -12+ V(12) – 4(4)(9) C) x =- 3 CD) x =- 2(4) 24. Solve for x. -12±(12) – 4(6)(4) 9+V177 D) x = CE) x = 2(6) 12 4x-6+9x? =0 9t(-9) - 4(6)(4) E) x = 3. V15 АВC) х — 4 25. Subsitute a, b, and c into the quadratic 2(6) 12 formula. ACO 2 ABD) x = 26. Solve for x. 4+(-4) – 4(9)(6) AB) x = 2(6) 4+ V(-4) – 4(12)(9) AC) x = 2,2/26 5x? +10 = x –12x +1 ABE) x = 2(9) 27. Subsitute a, b, and c into the quadratic formula. 12+ V(-12) - 4(4)(9) -2+V58 AD) x = ACD) x = 2(9) 28. Solve for x. 12 + V(-12) – 4(6)(4) -3+ 3 AE) x = ACE) x = 3 2(4) 6x +12x+7= 3 9+ V(-9)' – 4(6)(-4) 1 /26 BC) x = ADE) x = 6. 29. Subsitute a, b, and c into the quadratic 2(6) formula. 30. Solve for x.
Transcribed Image Text:Given a quadratic equation, write in standard form and then substitute the values of a, b, and c into the quadratic formula. Solve the equation by using the quadratic formula. 7x -9x-5=x -1 21. Subsitute a, b, and c into the quadratic C Choices for 21-30: formula. CE 22. Solve for x. 4+ (-4)° – 4(12)(9) A) x = 1 BD) x ==+- 3 2(12) x -x-6= 3x-11x – 15 -4 + V(4) – 4(9)(-6) 3+ V3 BE) x = B) x = 2(9) 23. Subsitute a, b, and c into the quadratic 4 formula. -12+ V(12) – 4(4)(9) C) x =- 3 CD) x =- 2(4) 24. Solve for x. -12±(12) – 4(6)(4) 9+V177 D) x = CE) x = 2(6) 12 4x-6+9x? =0 9t(-9) - 4(6)(4) E) x = 3. V15 АВC) х — 4 25. Subsitute a, b, and c into the quadratic 2(6) 12 formula. ACO 2 ABD) x = 26. Solve for x. 4+(-4) – 4(9)(6) AB) x = 2(6) 4+ V(-4) – 4(12)(9) AC) x = 2,2/26 5x? +10 = x –12x +1 ABE) x = 2(9) 27. Subsitute a, b, and c into the quadratic formula. 12+ V(-12) - 4(4)(9) -2+V58 AD) x = ACD) x = 2(9) 28. Solve for x. 12 + V(-12) – 4(6)(4) -3+ 3 AE) x = ACE) x = 3 2(4) 6x +12x+7= 3 9+ V(-9)' – 4(6)(-4) 1 /26 BC) x = ADE) x = 6. 29. Subsitute a, b, and c into the quadratic 2(6) formula. 30. Solve for x.
Write the quadratic equation in standard form and then find the value of the discriminant for the quadratic equation. Identify the number and nature of the solution. 4x =x+2 ABC 41. Value of the discriminant 42. Number and nature of the solution Choices for value of discriminant: A) -144 CD) 17 2x2 -1=5x+2 B) -95 CE) 24 43. Value of the discriminant C) -76 DE) 32 D) -72 АВC) 33 44. Number and nature of the solution E) -71 ABD) 49 АB) -63 ABE) 52 AC) -55 ACD) 73 x+9=3-3x? ACE) 109 AD) -24 45. Value of the discriminant AE) -18 ADE) 144 BC) 0 BCD) 145 46. Number and nature of the solution BD) 1 ВСЕ) 185 BE) 15 BDE) 200 8x - 5x+1=3x² –5 Choices for number and nature of solution: 47. Value of the discriminant 5 A) One real B) Two real 48. Number and nature of the solution C) One imaginary D) Two imaginary 16-12x = 12x-9x² 3C 49. Value of the discriminant 50. Number and nature of the solution K 2x +6x+1=3x² +6x-5 CE 51. Value of the discriminant 52. Number and nature of the solution
Transcribed Image Text:Write the quadratic equation in standard form and then find the value of the discriminant for the quadratic equation. Identify the number and nature of the solution. 4x =x+2 ABC 41. Value of the discriminant 42. Number and nature of the solution Choices for value of discriminant: A) -144 CD) 17 2x2 -1=5x+2 B) -95 CE) 24 43. Value of the discriminant C) -76 DE) 32 D) -72 АВC) 33 44. Number and nature of the solution E) -71 ABD) 49 АB) -63 ABE) 52 AC) -55 ACD) 73 x+9=3-3x? ACE) 109 AD) -24 45. Value of the discriminant AE) -18 ADE) 144 BC) 0 BCD) 145 46. Number and nature of the solution BD) 1 ВСЕ) 185 BE) 15 BDE) 200 8x - 5x+1=3x² –5 Choices for number and nature of solution: 47. Value of the discriminant 5 A) One real B) Two real 48. Number and nature of the solution C) One imaginary D) Two imaginary 16-12x = 12x-9x² 3C 49. Value of the discriminant 50. Number and nature of the solution K 2x +6x+1=3x² +6x-5 CE 51. Value of the discriminant 52. Number and nature of the solution
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