GIVEN: a>0, The surface, 2: x+y+z = a, x ≥ 0, y ≥ 0, z ≥ 0. Consider the 3D field: F (x+y, z, y - x) Orient the surface so that its normal vector to it has a positive z- component. Here is the canonical parameterization of 22: D:D, P(x, y) = (x, y, a- x - y) where D = {(x, y) = 0 ≤ x ≤ a 0 ≤ y ≤ a- FIND: The flux of F through 2 with the given orientation. A X Ω F = Add extra pages, as needed. A = (a,0,0) B=(0, a,0) C = (0,0,a) B (x + y, z, y - x) Y

Algebra & Trigonometry with Analytic Geometry
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ISBN:9781133382119
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Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 18T
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[20] (2)
GIVEN: a>0, The surface, Q2: x+y+z = a, x ≥ 0, y ≥ 0, z ≥ 0.
Consider the 3D field: F= (x, 2x, 3x)
Orient the surface so that its normal vector has a positive z- component.
FIND: The flux of F through 2 with the given orientation.
Parameterization of D:
D = PROJ, &:D Q
xy
= {(²₂₂) |0 ≤ y ≤a-x}
$(x,y)=(x, y, a-x-y)
⇒
= (1,0,-1) canonical
*y = (0,1,-1)
⇒ x = (1,1,1)
=
parameterization
A
a
J
A = (a,0,0)
B = (0, a, 0)
C = (0,0,a)
F = (x, 2x, 3x)
D=A
B
y=a-x
a
FLUX = √ F•áŠ = √ (2,22,32)-(1,1,1) dedy
= √₂ 6x dx dy = 65 ª 1 * x² dyd
бу
a
a
6 ["²x (2-x) b = 6 √ ² x ² + ax de
6 [ - ‡ a³ + + a²³²]
3
Y
Transcribed Image Text:[20] (2) GIVEN: a>0, The surface, Q2: x+y+z = a, x ≥ 0, y ≥ 0, z ≥ 0. Consider the 3D field: F= (x, 2x, 3x) Orient the surface so that its normal vector has a positive z- component. FIND: The flux of F through 2 with the given orientation. Parameterization of D: D = PROJ, &:D Q xy = {(²₂₂) |0 ≤ y ≤a-x} $(x,y)=(x, y, a-x-y) ⇒ = (1,0,-1) canonical *y = (0,1,-1) ⇒ x = (1,1,1) = parameterization A a J A = (a,0,0) B = (0, a, 0) C = (0,0,a) F = (x, 2x, 3x) D=A B y=a-x a FLUX = √ F•áŠ = √ (2,22,32)-(1,1,1) dedy = √₂ 6x dx dy = 65 ª 1 * x² dyd бу a a 6 ["²x (2-x) b = 6 √ ² x ² + ax de 6 [ - ‡ a³ + + a²³²] 3 Y
[10] (5)
: x + y + z = a, x ≥ 0, y ≥ 0, z ≥ 0.
(x + y, z, y - x)
Orient the surface so that its normal vector to it has a positive z - component.
GIVEN: a>0, The surface,
Consider the 3D field: F
Here is the canonical parameterization of Q:
Þ:D →
→ Ω, Φ(x, y)
(x, y, a- x - y)
where D = x, y
=
=
0 ≤ x ≤ a
0 ≤ y ≤a-
FIND: The flux of F through
with the given orientation.
A
X
Ω
Add extra
pages, as
needed.
A = (a,0,0)
B = (0,a,0)
C = (0,0, a)
B
F = (x+y, z, y - x)
Y
Transcribed Image Text:[10] (5) : x + y + z = a, x ≥ 0, y ≥ 0, z ≥ 0. (x + y, z, y - x) Orient the surface so that its normal vector to it has a positive z - component. GIVEN: a>0, The surface, Consider the 3D field: F Here is the canonical parameterization of Q: Þ:D → → Ω, Φ(x, y) (x, y, a- x - y) where D = x, y = = 0 ≤ x ≤ a 0 ≤ y ≤a- FIND: The flux of F through with the given orientation. A X Ω Add extra pages, as needed. A = (a,0,0) B = (0,a,0) C = (0,0, a) B F = (x+y, z, y - x) Y
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