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Given f (8)-3, f'(8)--5, find the equation of the tangent line at x - 8a)y+3(x-8)b) Oy +5 -3(r - 8)c)3-(x - 8)

Question
Given f (8)-3, f'(8)--5, find the equation of the tangent line at x - 8
a)
y+3
(x-8)
b) Oy +5 -3(r - 8)
c)
3-(x - 8)
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Given f (8)-3, f'(8)--5, find the equation of the tangent line at x - 8 a) y+3 (x-8) b) Oy +5 -3(r - 8) c) 3-(x - 8)

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Step 1

We have been given f(8) = 3 and f'(8) = -5 and we need to find the equation of tangent line x=8.

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Step 2

We can use the value f(8)=3 to write the point (x1,y1) = (8,3). In addition to that, from the derivative f\'(8) = -5, we know that slope of the tangent line would be -5.

We know that general equation of a line with a known point and known slope  - aka - point slope form of line, is given as:

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Step 3

Substituting the given slope and point in the point slope for...

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Math

Calculus

Derivative

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