Question

Step 1

We have been given f(8) = 3 and f'(8) = -5 and we need to find the equation of tangent line x=8.

Step 2

We can use the value f(8)=3 to write the point (x1,y1) = (8,3). In addition to that, from the derivative f\'(8) = -5, we know that slope of the tangent line would be -5.

We know that general equation of a line with a known point and known slope - aka -** point slope form** of line, is given as:

Step 3

Substituting the given slope and point in the point slope for...

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