Given fog(x) = √x³ + 3x² + 3x + 1, state two different possible sets of functions for f(x) and g(x). ii) f(x)= f(x)= g(x)= g(x)=

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 5T
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Given fog(x)=√x³ + 3x² + 3x + 1, state two different possible sets of functions for f(x) and g(x).
f(x)=
ii) f(x)=
g(x)=
g(x)=
Given f(x)=√x+1, g(x) = 3*,h(x) = cosx, m(x) = log[-(x-4)] and p(x)
The equation in fully simplified form
a. f(x) + g(x)
b. g(x) - m(x)
c. f(x)p(x)
d. h(x) + p(x)
=
x-3
Domain
Transcribed Image Text:Given fog(x)=√x³ + 3x² + 3x + 1, state two different possible sets of functions for f(x) and g(x). f(x)= ii) f(x)= g(x)= g(x)= Given f(x)=√x+1, g(x) = 3*,h(x) = cosx, m(x) = log[-(x-4)] and p(x) The equation in fully simplified form a. f(x) + g(x) b. g(x) - m(x) c. f(x)p(x) d. h(x) + p(x) = x-3 Domain
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