Given numPQueue: 29, 38, 76 What does Peek(numPQueue) return? Ex: 100 After the following operations: Enqueue(numPQueue, 89) Enqueue(numPQueue, 84) Peek(numPQueue) Dequeue(numPQueue) What is numPQueue? Ex: 1, 2, 3 What does GetLength (numPQueue) return? Ex: 1

Given numPQueue: 29, 38, 76 What does Peek(numPQueue) return? Ex: 100 After the following operations: Enqueue(numPQueue, 89) Enqueue(numPQueue, 84) Peek(numPQueue) Dequeue(numPQueue) What is numPQueue? Ex: 1, 2, 3 What does GetLength (numPQueue) return? Ex: 1

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Implement a __setitem__ function that also supports negative indices. For example: W = L2(Node(10, Node(20, Node(30))))print W[ 10, 20, 30 ] W[1]=25print W[ 10, 25, 30 ] W[-1]=35print W[ 10, 25, 35 ] Complete the code: def L2(*args,**kwargs): class L2_class(L): def __getitem__(self, idx): <... YOUR CODE HERE ...> def __setitem__(self, idx, value): <... YOUR CODE HERE ...> return L2_class(*args,**kwargs) W = L2(Node(10, Node(20, Node(30))))print(W)W[1]=25print(W)W[-1]=35print(W)
Given the following function, what happens if a[] contains just one element that doesn't match val? int binarySearch(int a[], int first, int last, int val){ if (first > last) return -1; int middle = (first + last) / 2; if (a[middle] == val) return middle; if (a[middle] < val) return binarySearch(a, middle+1, last, val); else return binarySearch(a, first, middle-1, val);} Group of answer choices binarySearch never calls itself again and terminates (recursion never happens) binarySearch calls itself once then terminates (recursion happens once) binarySearch calls itself twice then terminates (recursion happens twice) binarySearch calls itself 3 times then terminates (recursion happens 3 times)
Retrieving a value using its associated key can be accomplished using anindexer, which works just like an indexer for an array. A key is passed in asthe index value, and the value associated with the key is returned, unless thekey doesn’t exist, in which a null is returned.Write short code segment demonstrates how this technique works:
The following are the operations that you can do using a single linked list. Choose only one operation then create the algorithm and simulate. The attached Rubric will be used in evaluating the activity. 1. Delete a particular node in a single linked list 2. Delete the first node of a single linked list 3. Insertion after a given node of a single linked list 4. Insertion at a given position in a single linked list 5. Insertion before a given node in a single linked list 6. Reverse a single linked list EX: Delete the last node of a single linked list Problem" Deletion of the last node in a single linked list Algorithm" Step 1: if HEAD = NULL Write UNDERFLOW Go to Step 8 Step 2: SET PTR = HEAD Step 3: Repeat Steps 4 and while PTR à NEXT = NULL Step 4: SET PREPPTR = PTR Step 5: SET PTR =PTR à NEXT [End of loop] Step 6: SET PREPTR à NEXT = NULL Step 7: FREE PTR Step 8: EXIT…
JAVA Create a class Book with the following attributesBooKname, BookPublisher, BookYearofPublished5.1 Now create the collection of book objects using treeset and do the followingoperations• Sort by bookname• Reverse sort by bookyearofpublished5.2 Now create the collection of book objects using LinkedHashSet and do thefollowing operation• sort by bookpublisher
betterAddProduct Write a method in your Warehouse class to further optimize addProduct. As of now, it’s possible that an item is removed from a full sector to make room for a new product, even if there are other sectors which are not full. If the current sector is not full, add the product as normal. Otherwise perform a linear probing-like operation to try to find a non-full sector (if the current one is full). Keep incrementing the sector until you either find one with space, or you return to your original sector. If you get to Sector 9, wrap around to Sector 0. If you found a new sector with space, add the product into this sector. In a real-world scenario we would have to make sure to change the ID in our system and make sure it doesn’t conflict with an existing one. In this assignment that is not necessary since the output only contains the name. If you returned to the original sector, perform eviction and add the product as normal.
Complete and submit LinkedStack2.java with following: Inherit LinkedStack.java, implement StackInterface2.java Add String toString()method as specified in page 153, problem 28(a) Add int size()method as specified in page 153, problem 28(b) Add void popSome(int count)method as specified in page 153, problem 28(c) Add boolean swapStart()method as specified in page 153, problem 28(d) Add T poptop() method as specified in page 153, problem 28(e)
OZ PROGRAMMING LANGUAGE Exercise 1. (Efficient Recurrence Relations Calculation) At slide 54 of Lecture 10, we have seen aconcurrent implementation of classical Fibonacci recurrence. This is: fun {Fib X} if X==0 then 0 elseif X==1 then 1 else thread {Fib X-1} end + {Fib X-2} end end By calling Fib for actual parameter value 6, we get the following execution containing several calls ofthe same actual parameters.For example, F3, that stands for {Fib 3}, is calculated independently three times (although it providesthe same value every time). Write an efficient Oz implementation that is doing a function call for a givenactual parameter only once.Consider a more general recurrence relation, e.g.:F0, F1, ..., Fm-1 are known as initial values.Fn = g(Fn-1, ..., Fn-m), for any n ≥ m.For example, Fibonacci recurrence has m=2, g(x, y) = x+y, F0=F1=1
Implement a city database using ordered lists by using java. Each database record contains the name of the city (a string of arbitrary length) and the coordinates of the city expressed as integer x and y coordinates. Your database should allow records to be inserted, deleted by name, and searched by name. Another operation that should be supported is to print all records within a given distance of a specified point/coordinate. The order of cities should be alphabetically by city name. Implement the database using both: an arraybased list implementation, and a circular single linked list implementation.Use may the following node, SLL implementations to implement an ordered circular single linked list
Java Simulate the behavior of a hash map. Assume the following: the hash table array has an initial capacity of 10 the hash table uses separate chaining to resolve collisions and adds new values at the beginning of the linked list. the hash function returns the absolute value of the integer key, mod the capacity of the hash table rehashing occurs at the end of an add where the load factor is ≥ 0.5 and doubles the capacity of the hash table Fill in the diagram to show the final state of the hash table after the following operations are performed. Write each bucket as key:value pairs with arrows between them, such as key1:value1 -> key2:value2 -> key3:value3 . Put a \ in the box if an array element is unused. Also write the size, capacity, and load factor of the final hash table. Write the load factor in 0.x format, such as 0.5 or 0.75. hashTable[ 0 ] : _____ hashTable[ 1 ] hashTable[ 2 ] hashTable[ 3 ] hashTable[ 4 ] hashTable[ 5 ] hashTable[ 6 ] hashTable[ 7 ] hashTable[ 8 ]…
Consider the following functions are called for an integer queue in order. What will be the final state of the queue after these operations?CreateQueue(Q);Enqueue(9, Q);Enqueue(1, Q);Dequeue(&x, Q);Enqueue(4, Q);ClearQueue(Q);Enqueue(1, Q);QueueGetFront(&x, Q);Enqueue(7, Q);Dequeue(&x, Q);Enqueue(9, Q);Enqueue(2, Q);Dequeue(&x, Q);Enqueue(3,Q);
Assume we wish to resize an existing hash table because the current hash table is becoming too small for the application. Without writing code briefly describe the process of resizing a hash table by "copying" the old data to the new hash table. What is the expected complexity of your process using Big-O notation. Justify your complexity measure. An example of a hash table before resizing is given.