Given R, = 20 kQ, R2 = 10 kN, R3 = 50 kn , R4 = 10 kn, V, = 300 V and V2 = 1200 V, find the finite difference approximation to the potential points 1,5, 10 and 11 of the system in Figure 3 using iteration method. Limit the iteration to 2 only. Note that the nodal voltage should be in proper sequence that is node 1, 2, 3, 4, 5, 6, 7, 8, 9,10,11,12,13,14,15 and 16. %3D %3D %3D

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Given R, = 20 kQ, R2 = 10 kQ, R3 = 50 kn , R4 = 10 kQ, V, = 300 V and V2 = 1200 V,
find the finite difference approximation to the potential points 1,5, 10 and 11 of the
system in Figure 3 using iteration method. Limit the iteration to 2 only. Note that the
nodal voltage should be in proper sequence that is node 1, 2, 3, 4, 5, 6, 7, 8,
9,10,11,12,13,14,15 and 16.
%3D
Not connected
R3
R1
2
3
V:
8
7
5
4
V1
13
R2
10
12
R4
16
15
14
Not connected
Not connected
6.
Transcribed Image Text:Given R, = 20 kQ, R2 = 10 kQ, R3 = 50 kn , R4 = 10 kQ, V, = 300 V and V2 = 1200 V, find the finite difference approximation to the potential points 1,5, 10 and 11 of the system in Figure 3 using iteration method. Limit the iteration to 2 only. Note that the nodal voltage should be in proper sequence that is node 1, 2, 3, 4, 5, 6, 7, 8, 9,10,11,12,13,14,15 and 16. %3D Not connected R3 R1 2 3 V: 8 7 5 4 V1 13 R2 10 12 R4 16 15 14 Not connected Not connected 6.
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