Given that f(x) = x² – 15x and g(x) = x + 14, find (a) (f + g)( – 3) = - %3D (b) (f – g)( – 3) = - (c) (fg)( – 3) = (-3) (d)

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Q: 3.y=1x² -2x リ=(x-2x)。 dy=$(x²-2x)*x (2x-2) -2x) 12 (2x-2 %3D /2-) メ 2メ-2 d メ-

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Q: How do I solve

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Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.