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Given that sine = 4/5 and e lies in quadrant II, find the following value. %3D csce 5/4 4/5 5/3

Given that sine = 4/5 and e lies in quadrant II, find the following value. %3D csce 5/4 4/5 5/3

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 64E
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Refer to the table below if needed. Second Quadrant Third Quadrant Fourth Quadrant sin(180° -e) = sine sin(180. +e) = - sine sin(360° -e) = - sine cos(180° -e) = - cose cos(180° +e) = - cose cos(360° -e) = cose %3D tan(1800 -e) = - tane tan(1800 +e) = tane tan(360. -e) = - tane cot(1800 -e) = - cote cot(180° +e) = cote cot(360. -e) = - cote sec(180° -e) = - sece sec(180° +e) = - sece sec(360° -e) = sece csc(180° -e) = csce csc(1800 +e) = - cSCe csc(360° -e) = - csce Given that sine = 4/5 and e lies in quadrant II, find the following value. csce 5/4 4/5 5/3
Transcribed Image Text:Refer to the table below if needed. Second Quadrant Third Quadrant Fourth Quadrant sin(180° -e) = sine sin(180. +e) = - sine sin(360° -e) = - sine cos(180° -e) = - cose cos(180° +e) = - cose cos(360° -e) = cose %3D tan(1800 -e) = - tane tan(1800 +e) = tane tan(360. -e) = - tane cot(1800 -e) = - cote cot(180° +e) = cote cot(360. -e) = - cote sec(180° -e) = - sece sec(180° +e) = - sece sec(360° -e) = sece csc(180° -e) = csce csc(1800 +e) = - cSCe csc(360° -e) = - csce Given that sine = 4/5 and e lies in quadrant II, find the following value. csce 5/4 4/5 5/3
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