GIVEN THE ANSWERS (YELLOW HIGHLIGHT) PLEASE SHOW THE SOLUTION Four simple curves (CURVE 1 CURVE 2 CURVE 3 are connected to form the highway curves CURVE 2 formed a compound curve with CURVE 1 CURVE 2 also formed a reverse curve with CURVE 3 The common tangent of the compound curve is parallel to its long chord The reverse curve has parallel tangents CURVE 1 Radius = 800 meter s CURVE 1 Long Chord =170 meters CURVE 1 Stationing of PI 9 + 578.40 CURVE 2 Radius = 520 meters CURVE 2 Long Chord = 135 meters CURVE 3 Radius = 750 meters CURVE 3 Long Chord = 221 meters
GIVEN THE ANSWERS (YELLOW HIGHLIGHT) PLEASE SHOW THE SOLUTION Four simple curves (CURVE 1 CURVE 2 CURVE 3 are connected to form the highway curves CURVE 2 formed a compound curve with CURVE 1 CURVE 2 also formed a reverse curve with CURVE 3 The common tangent of the compound curve is parallel to its long chord The reverse curve has parallel tangents CURVE 1 Radius = 800 meter s CURVE 1 Long Chord =170 meters CURVE 1 Stationing of PI 9 + 578.40 CURVE 2 Radius = 520 meters CURVE 2 Long Chord = 135 meters CURVE 3 Radius = 750 meters CURVE 3 Long Chord = 221 meters
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
GIVEN THE ANSWERS (YELLOW HIGHLIGHT) PLEASE SHOW THE SOLUTION
Four simple curves (CURVE 1 CURVE 2 CURVE 3 are connected to form the highway curves CURVE 2 formed a compound curve with CURVE 1 CURVE 2 also formed a reverse curve with CURVE 3 The common tangent of the compound curve is parallel to its long chord The reverse curve has parallel
tangents
CURVE 1 Radius = 800 meter s
CURVE 1 Long Chord =170 meters
CURVE 1 Stationing of PI 9 + 578.40
CURVE 2 Radius = 520 meters
CURVE 2 Long Chord = 135 meters
CURVE 3 Radius = 750 meters
CURVE 3 Long Chord = 221 meters
![Using arc basis, compute the following and answer the following questions:
1. What is the stationing of PC of the compound curve?
2. What is the stationing of PCC of the compound curve?
3. What is the stationing of PRC of the reverse curve?
4. What is the stationing of PT of the reverse curve?
9 + 492.90
9 + 663.24
STA. PC 9,492.90
or
STA. PCC 9,663.24
or
STA. PRC 9,798.65
9 + 798.65
or
STA. PT 10,020.39
10 + 20.39
or](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F549d51d3-8e61-4279-9a7d-fec056cb3f98%2F68e527f1-0dec-4e15-a67c-f2e4c9638567%2F1eadq2c_processed.png&w=3840&q=75)
Transcribed Image Text:Using arc basis, compute the following and answer the following questions:
1. What is the stationing of PC of the compound curve?
2. What is the stationing of PCC of the compound curve?
3. What is the stationing of PRC of the reverse curve?
4. What is the stationing of PT of the reverse curve?
9 + 492.90
9 + 663.24
STA. PC 9,492.90
or
STA. PCC 9,663.24
or
STA. PRC 9,798.65
9 + 798.65
or
STA. PT 10,020.39
10 + 20.39
or
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