Given the below network routing graph (with costs), answer the following questions that follow: N1 N4 N2 N5 10 3 N3 N6 (a) What is the path with the least cost when communicating between N1 and N6. Is this the only cost effective path? (b) Given the local datagram forwarding table for node N2 below and the destination address is 11100000 01110011 00100000 01100111, which link will this packet be forwarded to? What is this lookup technique called?

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Given the below network routing graph (with costs), answer the following questions that
follow:
N1
N4
5
6
N2
N5
10
N3
N6
(a) What is the path with the least cost when communicating between N1 and N6. Is
this the only cost effective path?
(b) Given the local datagram forwarding table for node N2 below and the destination
address is 11100000 01110011 00100000 01100111, which link will this packet be
forwarded to? What is this lookup technique called?
Destination Address range
11100000 01110011 00100000 01101***
11100000 01110011 00100000 011010**
11100000 01110011 00100000 011011**
Output Link Interface
N1
N3
N4
Otherwise
N6
3.
Transcribed Image Text:Given the below network routing graph (with costs), answer the following questions that follow: N1 N4 5 6 N2 N5 10 N3 N6 (a) What is the path with the least cost when communicating between N1 and N6. Is this the only cost effective path? (b) Given the local datagram forwarding table for node N2 below and the destination address is 11100000 01110011 00100000 01100111, which link will this packet be forwarded to? What is this lookup technique called? Destination Address range 11100000 01110011 00100000 01101*** 11100000 01110011 00100000 011010** 11100000 01110011 00100000 011011** Output Link Interface N1 N3 N4 Otherwise N6 3.
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