Given the curve y² = 5x – 1 at point ( 1,-2 ) , find the equation of tangent and normal to the curve. A. 5x + 4y + 3 = 0 & 4x- 5y- 14 = 0 B. 5x + 4y-3 = 0 & 4x + 5y- 14 = 0 C. 5x- 4y +3= 0 & 4x + 5y + 14 0 D. 5x- 4y-3 = 0 & 4x + 5y – 14 = 0 ズI

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