Please show your full solution. Given the data of a closed traversebelow, convert it into figure reflectingtheir corresponding values.AZIMUTHLINELENGTHFROM SOUTHАВ189.536°15'ВС175.18330°22'CD197.7898°42'DE142.39167°36'EA234.58222°59'

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Answered: Given the data of a closed traverse…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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3. The following data if a closed traverse is shown in the technical description. The area of the closed traverse is 63147.05 sq. m. LINES AB BC CD LAT. a -240.20 -160.00 DA 179.70 Solve for the unknown variables. DEP. 120 с e -220 DMD b d f 8 2A 26460.0 X -86480.0 39534.0
Situation 4] From the given data ofa dosed traverse, The adjusted bearing of BC using compassrule. The adjusted bearing of DA using compass rule. The total area using Coordinates method. The total area using Double Parallel Distance method. i. ii. i. iv. Distance, m 368.76 Bearing N15°18'E S85046'E S18°30W N77035W Line АВ ВС 645.38 CD 467.86 DA 593.00
Question 8 The angles about a point P were measured with the following number of measurements taken shown in the table below. Measured Angle Repitition Value APB 31° 15' ВРС 12° 16' 4. СPD 41° 28' 4 DPA 84° 53' Calculate the most probable value of angle BPC O 12°14' O 12°17 O 12°18' O 12°15'
8. Compute for the following and show the tabulated solutions: Azimuth LINES Length (S) АВ 1020.87 168d35m ВС 1117.26 263d30m CD 660.08 304d25m DE 495.85 5d30m EF 850.62 46d15m FA 855.45 112d30m (lengths in 3 dec. places; bearings in deg-mm-ss) a. Using Transit Rule, solve for adjusted latitudes, departures, distances, and bearings for all the traverse lines Lines Adj. Latitude Adj. Departure Adj. Length Adj. Bearing AB BC CD DE EF FA
30 Y 5OKN 3. 4 40° 7OKN 450 l00 KN z Fy=? ī Fx = ? %3D RF = ? %3D 20
PROBLEM 1. Given in the accompanying tabulation are the adjusted latitude and adjusted departure of a closed traverse. Calculate the area by the DMD method LINE ADJ ADJ LAT DEP AB - 125.055 + 196.387 BC +20.241 + 241.003 CD +180.107 + 65.326 DE +210.169 - 104.519 EF -74.003 - 260.516 FA - 211.459 - 137.681
Determine the force of all members using METHOD OF JOINT. Answer in 3 decimal places only. TRUSS MEMBERS ● FORCE COMPRESSION OR TENSION
From the following measured interiror angles of a five sided figure, compute the following: Station Values of Angles (No. of Measurements A 110.00 98.000 108.00 120.00 105.00 BUDE с 5 NOTE: Final answer must be in decimal degrees. HINT: Sum of Interior Angles = (n-2)*180* NAO сл 6 4 2 1 a) Probable value of Angle A. b) Probable value of Angle C. °c) Probable value of Angle D
PROBLEM 17: The following are bearings and distances taken on a closed traverse. Bearing N60°E Line Distances АВ 1000 m ВС Due South N60°W A line from vertex A to point F on the side BC divides the area and makes area ABF to be 280 000 m?. Find the length of the line AF. CA a. 878.35 m b. 750,12 m c. 646.63 m d. 593.30 m
The people in Metropolis made a tribute for Clark Kent and performed a survey to form his crest as shown in the figure. The course of the traverse is alphabetical (A-B-C-D-E-A). Determine the following: a. The unknown angle at point E. b. The bearings and azimuths (from north and south) of all the lines of the traverse assuming that line AB has a bearing of S 75°30' E.
2. What are the radian and degree-minute-second equivalents for the following angles given in grads: (a)* 136.000 grads (b) 115.089 grads ???°??′??″; 1.80781 rad (c) 363.809 grads ???°??′??″; 5.71469 rad
Q7) Calculate the coordinates. Check whether the error is acceptable. Make corrections. N 59.0701g S2 145.5558g S1 161.51849 A x=315.122m $3 S6 120.6210g 167.8089g S4 F S5 Y (m) x (m) Дх B (grad) a (grad) S (m) Ay STATION A 137.619 214.077 170.542 D 189.664 225.219 F 156.907 A 8 y=74.056m

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Given the data of a closed traverse below, convert it into figure reflecting their corresponding values. AZIMUTH LINE LENGTH FROM SOUTH AB 189.53 6°15' ВС 175.18 330°22' CD 197.78 98°42' DE 142.39 167°36' EA 234.58 222°59'