Given the differential equation (2D2 – 3D+ 1) y = csc(2ra) - Propose an appropriate particular solution. Take u1 and uz to be functions of x. Yp = u1e* + uze? %3D Yp = uj cos(x) + uz sin () Yp = u1e¯² +uze 2 Yp = u1 cos(-a) + u2 sin (-) %3D |

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the differential equation
(2D2 - 3D+1) y = csc(2rx)
= csc(2Tx)
Propose an appropriate particular solution. Take u1 and u2 to be
functions of x.
1
Yp = uje² + u»e
O yp = U1 cos(x) + u2 sin ()
%3D
CSOS
1
Yp = U1e¯ + uze 2
O yp = u1 cos(-x)+ u2 sin (-)
cos(-a) +
sin(-;)
Transcribed Image Text:Given the differential equation (2D2 - 3D+1) y = csc(2rx) = csc(2Tx) Propose an appropriate particular solution. Take u1 and u2 to be functions of x. 1 Yp = uje² + u»e O yp = U1 cos(x) + u2 sin () %3D CSOS 1 Yp = U1e¯ + uze 2 O yp = u1 cos(-x)+ u2 sin (-) cos(-a) + sin(-;)
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