Given the differential equation, its solution and the initial conditions, determine the value of the arbitrary constants: x′ + 2tx^(2) = 0, x(t) = (1/(t^(2)) + C), x(0) = 1.
Given the differential equation, its solution and the initial conditions, determine the value of the arbitrary constants: x′ + 2tx^(2) = 0, x(t) = (1/(t^(2)) + C), x(0) = 1.
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.1: Solutions Of Elementary And Separable Differential Equations
Problem 16E: Find the general solution for each differential equation. Verify that each solution satisfies the...
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x′ + 2tx^(2) = 0, x(t) = (1/(t^(2)) + C), x(0) = 1.
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