Given the following differential equation: (D² – 4) y = e-3= sin e- Using the method of variation of parameters, which to the given difforontial oguntion?

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Question
14.
Given the following differential equation:
(D² – 4) y = e-3z sin e-
|
Using the method of variation of parameters, which of the following equations result after the proposed particular solution is substituted
to the given differential equation?
O A' (x) cos 2a + B' (x) sin 2x = 0
-2A' (x) sin 2x + 2 B' (x) cos 2x = e
-32 sin e?
O A' (x) e2 + B' (x) e = 0
-2z
2A' (x) e2 + 2B' (x) e-2 =
= e-3 sin e
O A' (x) cos 2x + B' (x) sin 2x = 0
2A' (x) sin 2x – 2B' (x) cos 2x = e-3 sin e
O A' (2) et + B' (2) = 0
2A' (x) e - 2B' (2) = e-* sin e
Transcribed Image Text:Given the following differential equation: (D² – 4) y = e-3z sin e- | Using the method of variation of parameters, which of the following equations result after the proposed particular solution is substituted to the given differential equation? O A' (x) cos 2a + B' (x) sin 2x = 0 -2A' (x) sin 2x + 2 B' (x) cos 2x = e -32 sin e? O A' (x) e2 + B' (x) e = 0 -2z 2A' (x) e2 + 2B' (x) e-2 = = e-3 sin e O A' (x) cos 2x + B' (x) sin 2x = 0 2A' (x) sin 2x – 2B' (x) cos 2x = e-3 sin e O A' (2) et + B' (2) = 0 2A' (x) e - 2B' (2) = e-* sin e
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