Given the following general solution 00 E (R + 1) + 3 A * (R-2) A = 0 R = 1 Set the coefficient portion of the power series equal to 0 and then solve for " AR +1". A ^(R+1) = (3R – 6) a, R ® A (R + 1) = R - 2 + 3A, 3 AR OA (R+1) %3D R - 2 -3 A, R. A (R + 1) R- 2 EA (R + 1) = AR + R R - 2 PA (R+1) 3 AR

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