Given the following integral of a trigonometric function raised to an odd power Scos(2x) dx Use the formulas discussed in the lecture to convert the trigonometric function into the correct form. cos (2:) cos(29 - [1 - sin?(2»)]5 sin(2x) 2cos(2x) 2cos(2x) dx dx cos(2x) con(2) - [1 - sin2(2x)] ² sin(2) Acos(2x) dx tcos(2x) dx cos(2:) cos(2) - [1 - sin?(2x)] sin(2x) 2cos(2x) 2cos(2x) dx cas (2:) cos(29 - [1 - sin2(2x)] sin(2x) 2cos(2x) dx 2cos(2x) dx

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